I think the correct answer is D: Potential Energy.
According to Newton laws of motion,
F = m*a
Here, m = 1,560 Kg
a = 1.30 m/s²
Substitute their values,
F = 1,560 * 1.30
F = 2028 N ~ 2030 N [ Closest value ]
In short, Your Answer would be Option C
Hope this helps!
Answer:
the work done by the motor is 531,45 Joules
Explanation:
Using a sketch of the possible conditions, we need to find the distance that the block was moved, in order to find the work done by the electrical motor.
The sketch could be seen in the attached image.
Answer:
Kf= 36 J
W(net) = 32 J
Explanation:
Given that
m = 2 kg
F= 4 N
t= 2 s
Initial velocity ,u= 2 m/s
We know that rate of change of linear momentum is called force.
F= dP/dt
F.t = ΔP
ΔP = Pf - Pi
ΔP = m v - m u
v= Final velocity
By putting the values
4 x 2 = 2 ( v - 2)
8 = 2 ( v - 2)
4 = v - 2
v= 6 m/s
The final kinetic energy Kf
Kf= 1/2 m v²
Kf= 0.5 x 2 x 6²
Kf= 36 J
Initial kinetic energy Ki
Ki = 1/2 m u²
Ki= 0.5 x 2 x 2²
Ki = 4 J
We know that net work is equal to the change in kinetic energy
W(net) = Kf - Ki
W(net) = 36 - 4
W(net) = 32 J
