Ask question

Ask question

All categories

2 years ago

11

Accelerating car is a _______

2 answers:

Pavel [41]2 years ago

5 0

Acceleration is the rate of change of velocity as a function of time. For example a car traveling at 50 km/hr starts to accelerate, 10 seconds after, its speed changes to 100 km/hr then the acceleration of the car during the time can be calculated as below: initial speed = 50 km/hr.

Goshia [24]2 years ago

4 0

Answer: C.
Hint on to of why this is correct “ACCELERATING a car” glad I can help :)

You might be interested in

What provides the force that causes magma to erupt to the surface

olga2289 [7]

Geothermal energy provides force that causes magma to erupt to the surface

3 0

3 years ago

Calculate the kinetic energy in joules of a 1200 kg automobile moving at 18 m/s .

vodka [1.7K]

Answer:

194,400 joules of kinetic energy.

Explanation:

Remember that to calculate the Kinetic energy you need to use the next formula:

$Ke=\frac{1}{2}Mass*Velocity^2$

We know that Mass= 1200 kg and velocity is 18m/s, so we insert those values into the formula:

$Ke=\frac{1}{2}Mass*Velocity^2\\Ke=\frac{1}{2}1200kg*(18m/s)^2\\Ke=194,400 joules$

So the kinetic energy of a car moving at 18m/s with a mass of 1200 kg would be 194,400 joules.

7 0

3 years ago

Read 2 more answers

The average kinetic energy of the particles in an object is directly proportional to its A) heat. B) volume. C) temperature. D)

yanalaym [24]

the average kinetic energy of the particles in an object is directly proportional to its TEMPERATURE.

5 0

3 years ago

Read 2 more answers

What do we call the small changes that

Lelu [443]

Answer:

The "butterfly Effect"

Explanation:

The "butterfly effect" will probably have big changes in the future.

6 0

3 years ago

On a vacation flight, you look out the window of the jet and wonder about the forces exerted on the window. Suppose the air outs

user100 [1]

Answer:

A) $\Delta P = 14512.5 Pa = 14.512 kPa$

B) F = 1632.65 N

Explanation:

Given details

outside air speed is given as $v_2 = 150 m/s$

since inside air is atmospheric , $v_1 = 0 m/s$

a) By using bernoulli equation between outside and inside of flight

$P_1 + \frac{1}{2} \rho v_1^2 + \rho gh = P_2 + \frac{1}{2} \rho v_2^2 + \rho gh$

$\Delta P = \frac{1}{2} \rho v_2^2 - \frac{1}{2} \rho v_1^2$

$\Delta P = \frac{1}{2} \rho[ v_2^2 -v_1^2]$

$\Delta P = \frac{1}{2} 1.29 [ 150^2 - 0^2]$

$\Delta P = 14512.5 Pa = 14.512 kPa$

b) force exerted on window

Area of window $= 25\times 45 = 1125 cm^2 = 0.1125 m^2$

We know that force is given as

$F = P\times A$

$F = 14512.5 \times 0.1125$

F = 1632.65 N

5 0

4 years ago