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3 years ago

In terms of positive and negative charges what causes lightning?

Physics

1 answer:

erik [133]3 years ago

7 0

Answer:

Electrostatic Discharge during the equalization of the separated positively and negatively charged electrostatic charges in the storm clouds.

Explanation:

In nature, lightning occurs during the discharge of the large charges contained in the separated positively and negatively particles in the atmosphere in the process equalizing (neutralizing) of the charges, leading to the release of instantaneous energy in the form of heat, light and sound

During a storm, as the clouds mixes by the wind with different densities, they rub each other forming electrostatic charges. The lighter positively charged particles rise to the top clouds while the heavier negatively charged particles move to the bottom. The charges continue to add up to a point where their magnitudes is large enough such that a big spark or lightening occurs between the positive and negative charges during the process of re-equalization of the charges to revert to neutrality.

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choli [55]

Answer:

3. Her angular speed increases because her angular momentum is the same but her moment of inertia decreases

Explanation:

II ωi the intial angular momentum of the skater. Her angular momentum changes to If ωf after pulling her arms in.

It must be noted that If is less than II, then it is because her arms now go round not far from the rotation axis which brings down the mementos of inertia.

Angular momentum does not change since torque is O.

Note: the mathematical representations are better written on the attached diagram.

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4 years ago

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Particles of m1 and m2 (m2>m1) are connected by a line in extensible string passing over a smooth fixed pulley. Initially, bo

Tresset [83]

Answer:

The velocity with which the mass will hit the floor is $v_f = \sqrt{2(\dfrac{m_2-m_1}{m_2+m_1}) x.}$

Explanation:

If the tension in the string is $T$ , for $m_1$ we have

$T- m_1g =m_1a$ ,

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From these equations we solve for $a$ and get:

$a =(\dfrac{m_2-m_1}{m_2+m_1}) g.$

The kinematic equation

$v_f^2 = v_0^2+2ax$

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In our case

$v_0 = 0$ (the initial velocity of the particles is zero)

$a =(\dfrac{m_2-m_1}{m_2+m_1}) g.$

which gives us

$v_f^2 = 2ax$

$v_f^2 =2(\dfrac{m_2-m_1}{m_2+m_1}) g$

$\boxed{v_f = \sqrt{2(\dfrac{m_2-m_1}{m_2+m_1}) x.} }$

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3 years ago

A Porsche 944 Turbo has a rated engine power of 217 hp. 30% of the power is lost in the drive train, and 70% reaches the wheels.

shutvik [7]

Answer:

a = 6.53 m/s^2

v = 11.5689 m/s

Explanation:

Given data:

engine power is 217 hp

70 % power reached to wheel

total mass ( car + driver) is 1530 kg

from the data given

2/3 rd of weight is over the wheel

w = 2/3rd mg

maximum force

$F = \mu W$

we know that F = ma

$ma = \mu (2/3 mg)$

$a_{max} = 2/3(1.00) (9.8) = 6.53 m/s^2$

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$P =f_{max} v$

$0.7P_{max} = ma_{max} v$

solving for speed v

$v =0.7 \times \frac{P_{max}}{ma_{max}}$

$v = 0.7 \frac{217 [\frac{746 w}{1 hp}]}{1500 \times 6.53}$

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ICE Princess25 [194]

Answer:

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3 years ago

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