Answer:
Time period of second planet will be 126.40 days
Explanation:
We have given radius of first planet
Orbital speed of first planet
Radius of second planet
We have to find orbital period of second planet
Period of orbital is equal to
From the relation we can see that
Time period of second planet will be 126.40 days
Answer:
Torque = 0.25Nm
Explanation:
To calculate the magnitude of torque, first we must calculate the lever arm. The lever arm is perpendicular distance from the axis of rotation to the line of the action of the force.
Lever arm = r sin theta
Where r = 4.9cm= 0.049m
Theta = 30°
Lever arm = 0.049 sin30° = 0.245m
Magnitude of torque = rfsintheta
f = 1.0T
Magnitude of torque= 0.245×1.0 = 0.245Nm
To 2 significant figure=0.25Nm
Answer:
In a concave mirror, if an object is located between the center of curvature and the focal point, what is the best way to describe the image formed? Real, inverted, and smaller than the object. Real, inverted, and larger than the object. light rays travel parallel to each other, no other image is formed.
Explanation:
Every atom has no overall charge (neutral). This is because they contain equal numbers of positive protons and negative electrons. These opposite charges cancel each other out making the atom neutral.
Answer:
Explanation:
18 km / h
= 300 m / min
12 km / h = 200 m / min
distance travelled in 200 minutes = 300 x 200 = 60000 m
distance travelled in 50 minute in return journey = 200 x 50 = 10000 m
total distance travelled = 70000 m
total time = 250 minute
speed = 70000 / 250
= 280 m / min
= 16.8 km / h
Total displacement = 60000 - 10000 = 50000 m
total time = 250 min
velocity = 50000 / 250
= 200 m / min
= 12 km / h