Answer: C) No solution
Let’s solve this. First we need to put the first equation into y=mx+b form. Let’s do this now.
First equation-
2•4y=10
*subtract 2*
4y=8
*divide 4*
y=2
Now that we know the value of y, let’s substitute that into the second equation.
2•4y= -10
2•4(2)= -10
2•8= -10
16= -10
When solved, these equations produce a result where both sides do not equal each other. 16 does not equal -10, making this have no solution.
This is your answer! Hope this helps comment below for more questions :)
Start by changing both into improper fractions.
Multiply the denominator and whole number, the add the numerator.
2 x 2 + 1= 5
2 1/2= 5/2
1 x 4 + 3= 7
-1 3/4= -7/4
Now do 5/2 multiplied by the reciprocal of -7/4 which is -4/7.
5/2 x -4/7= -20/14
Simplify to -10/7 by dividing by 2
Change it to a mixed number
Answer is -1 3/7
Answer:
Step-by-step explanation:
5.1, please this is just a guess from using my head to calculate
Answer:
<h2><u>
=</u>
<u>
57
/ 514 </u>
<u>
(Decimal: 0.110895)</u></h2>
Step-by-step explanation:
57
/ 514
<u>= 57
/ 514
</u>
<u>(Decimal: 0.110895)</u>
<u></u>
<u></u>
<u></u>
<u></u>
<u></u>
<u></u>
<u></u>
<u></u>
<u></u>
<h2><u>
And if that is not what you are looking for here: </u></h2><h2><u>
</u></h2>
Rewrite the equation as
x
/14
= 5/
7
. x/
14
= 5/
7
Multiply both sides of the equation by
14.14 ⋅ x
/14
= 14
⋅
5
/7
Simplify both sides of the equation.
Tap for fewer steps...
Cancel the common factor of 14
.
Cancel the common factor.
14
⋅ x
/14
= 14
⋅
5
/7
Rewrite the expression.
x
=
14
⋅
5
/7
Simplify 14
⋅ 5/
7
.
Cancel the common factor of 7
.
Factor 7 out of 14
.
x
=
7
(
2
)
⋅
5/
7
Cancel the common factor.
x
=
7
⋅ 2
⋅ 5/
7
Rewrite the expression.
x =
2
⋅
5
Multiply 2 by 5
.
<u>x
=
10</u>
Given:
Polynomial is
.
Term
is added in the given polynomial.
To find:
The end behavior of new polynomial.
Solution:
Let,
.
New polynomial is



Highest power of x is 6 which is even and leading coefficient is negative. So,


Both ends of the graph will approach negative infinity.
Therefore, the correct option is A.