Answer:83.17 cm/s
Explanation:
Let positive x be negative direction and negative x be positive direction in this question
General equation of motion of SHM is
x= --------1
where is natural frequency of motion given by
=
Where K is spring constant
here A=23.7cm
And it is given it is again at 23.7 from equilibrium position having passed through the equilibrium once.
i.e. it covers this distance in sec
where T is the time period of oscillation i.e. returning to same place after T sec
therefore T=0.634 sec
differentiating equation 1 we get
v=cos
and =
=9.911rad/s
=
v=83.17 cm/s
To solve this problem it is necessary to apply the concepts related to internal torque, shear stress and the angle generated from the modulo of elasticity, torque, length and polar moment of inertia.
We will start by finding the angular velocity in units that allow us to find the total torque:
From the indicated variable of power, in English system this would be
With the power and angular velocity found, the torque would then be:
The torsion formula will allow us to find maximum stress due to the shear force acting on the body:
And finally the angle of twist
Therefore the anle of twist in the shaft at full power is 4.58°
Answer:
B. 1520 N
Explanation:
The weight of each object can be calculated by using the formula:
where m is the mass of the object and g the acceleration due to gravity.
- The mass of the cow is m = 410 kg, so its weight is
- The mass of the car is m = 565 kg, so its weight is
So, the difference in weight is
And the closest answer is
B. 1520 N
Answer: The answer is 700kg
Explanation: