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Scrat [10]
3 years ago
12

First to answer gets brainliest

Physics
1 answer:
marissa [1.9K]3 years ago
4 0
Letter na that would be the answer
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5. Susan exerted 400 newtons of force while pushing on a huge boulder. The boulder moved 0 meters. Calculate work.
Stells [14]

Answer:

0 J

Explanation:

Work is the product of force and distance in the direction of force.

The formula is ; Work = Force * Distance

Given that :

Force = 400 N

Distance = 0 meters

Work = 400 * 0 = 0 J

No work was done because the boulder did not move.

4 0
3 years ago
A car is moving at 19 m/s along a curve on a horizontal plane with radius of curvature 49m.
JulsSmile [24]

Answer:

\mu =0.75

Explanation:

<u>Frictional Force </u>

When the car is moving along the curve, it receives a force that tries to take it from the road. It's called centripetal force and the formula to compute it is:

F_c=m.a_c

The centripetal acceleration a_c is computed as

\displaystyle a_c=\frac{v^2}{r}

Where v is the tangent speed of the car and r is the radius of curvature. Replacing the formula into the first one

F_c=m.\frac{v^2}{r}

For the car to keep on the track, the friction must have the exact same value of the centripetal force and balance the forces. The friction force is computed as

F_r=\mu N

The normal force N is equal to the weight of the car, thus

F_r=\mu .m.g

Equating both forces

\displaystyle \mu .m.g=m.\frac{v^2}{r}

Simplifying

\displaystyle \mu =\frac{v^2}{rg}

Substituting the values

\displaystyle \mu =\frac{19^2}{(49)(9.8)}

\boxed{\mu =0.75}

7 0
3 years ago
Even when shut down after a period of normal use, a large commercial nuclear reactor transfers thermal energy at the rate of 150
Phoenix [80]

Answer:

The temperature of the core raises by 2.8^{o}C every second.

Explanation:

Since the average specific heat of the reactor core is 0.3349 kJ/kgC

It means that we require 0.3349 kJ of heat to raise the temperature of 1 kg of core material by 1 degree Celsius

Thus reactor core whose mass is 1.60\times 10^{5}kg will require

0.3349\times 1.60\times 10^{5}kJ\\\\=0.53584\times 10^{5}kJ

energy to raise it's temperature by 1 degree Celsius in 1 second

Hence by the concept of proportionately we can infer 150 MW of power will increase the temperature by

\frac{150\times 10^{6}}{0.53584\times 10^{8}}=2.8^{o}C/s

5 0
3 years ago
Why is the big bang called a theory?<br>​
viva [34]
There is no scientific way to prove that it happened it’s like a hypothesis without being able to test the hypothesis
5 0
3 years ago
Read 2 more answers
What is the power of an electric with a current of 0.5 A and a voltage of 120 V ? The formula for power is P =IV
zaharov [31]

Answer:

60Watts

Explanation:

Given parameters:

Current = 0.5A

Voltage  = 120V

Unknown

Power = ?

Solution:

The power in the electric circuit is the product of current and voltage;

      P = IV

Insert the given parameters and solve;

      P = 0.5 x 120

      P  = 60Watts

7 0
2 years ago
Read 2 more answers
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