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Vaselesa [24]
3 years ago
7

Use the net to find the area of the prism

Mathematics
1 answer:
DanielleElmas [232]3 years ago
4 0

The surface area is the prism is 108mm2.

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Help me please asap thank you
Korolek [52]

Answer:

3/5

Step-by-step explanation:

The line is going up so it is positive and it is over 3 and up 5 so it would be 3/5.

Hope this helps! Sry if i get it wrong!

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2 years ago
What is the derivative of y=tan(arcsin(x))?
Anuta_ua [19.1K]
Hello,

(tg(x))'=1/cos²(x)

(arcsin(x))'=1/√(1-x²)

cos²(arcsin(x))=1-sin²(arcsin(x))=1-x²


(tg(arcsin(x)))'= \dfrac{1}{cos(arcsin(x)))^2} * \dfrac{1}{\sqrt{1-x^2}} \\

=\dfrac{1}{1-sin(arcsin(x))^2}* \dfrac{1}{\sqrt{1-x^2}} \\

= \dfrac{1}{1-x^2} * \dfrac{1}{\sqrt{1-x^2}} \\

\boxed{= \dfrac{\sqrt{1-x^2}}{x^4-2x^2+1}}\\


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3 years ago
If (x^6)^y = x^3, then y = ___.<br><br> Show your work!
musickatia [10]
Y=x^-3...................
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3 years ago
Please please help please
Readme [11.4K]

Step-by-step explanation:

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