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3 years ago

Air pollution can cause lung tissue damage in animals. This is an example of the affecting the .

Physics

2 answers:

AURORKA [14]3 years ago

7 0

The negative impact of air pollution

julia-pushkina [17]3 years ago

3 0

Air pollution can cause lung tissue damage in animals. This is an example of the affecting the Respiratory system.

Explanation:

Humans survive because of the air they breathe. Without oxygen and carbon dioxide in an environment it would be impossible for us to live or exist. Hence the quality of the air we breathe is also a major factor which determines the quality of health we have.

When we inhale bad or polluted air it leads to suffocation which persists and will lead to respiratory problems like asthma, lung cancer and other harmful diseases which leads us to stay on permanent medication.

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An aluminum cylinder weighing 30 N, 6 cm in diameter and 40 cm long, is falling concentrically through a long vertical sleeve of

Georgia [21]

Answer: Velocity terminal = 0.093m/s

Explanation:

1. We start by evaluating the gap distance between the two cylinders as h = R(sleeve) - R(cylinder)

= (0.0604/2 - 0.06/2)m

= 2×10^-4

Surface are of the cylinder in the drop, which is required in order to evaluate the shearing stress can be expressed as A(cylinder) = π.d.L

= (π×0.06×0.4)m²

= 0.075m²

Since the force of the cylinder's weight is going to balance the shearing force on the walls, we can express the next equation and derive terminal velocity from it.

Shearing stress = u×V.terminal/h = 0.86×V/0.0002

= 4300Vterminal

Therefore, Fw = shearing stress × A

30N = 4300Vterminal × 0.075

V. terminal = 30/4300 m.s

V. terminal = 0.093m/s

4 0

3 years ago

Cmon Guys help your pal abigail

NemiM [27]

13-16 that is where they’re located at

8 0

3 years ago

A sphere of radius R contains charge Q spread uniformly throughout its volume. Find an expression for the electrostatic energy c

tensa zangetsu [6.8K]

Answer:

$E = \frac{3kQ^2}{5R}$

Explanation:

Let the sphere is uniformly charge to radius "r" and due to this charged sphere the electric potential on its surface is given as

$V = \frac{kq}{r}$

now we can say that

$q = \frac{Q}{\frac{4}{3}\pi R^3} (\frac{4}{3}\pi r^3)$

$q = \frac{Qr^3}{R^3}$

now electric potential is given as

$V = \frac{k\frac{Qr^3}{R^3}}{r}$

$V = \frac{kQr^2}{R^3}$

now work done to bring a small charge from infinite to the surface of this sphere is given as

$dW = V dq$

$dW = \frac{kQr^2}{R^3} dq$

here we know that

$dq = \frac{3Qr^2dr}{R^3}$

now the total energy of the sphere is given as

$E = \int dW$

$E = \int_0^R \frac{kQr^2}{R^3} (\frac{3Qr^2dr}{R^3})$

$E = \frac{3kQ^2}{R^6} (\frac{R^5}{5} - 0)$

$E = \frac{3kQ^2}{5R}$

7 0

3 years ago

which measurment describes the amount of heat needed to raise the temperature of one gram of a material by one degree celsius?

ella [17]

Answer:

Specific Heat

Explanation:

Specific heat is the measurement which describes the amount of heat needed to raise the temperature of one gram of a material by one degree Celsius.

It is the amount of heat required per unit mass to raise the temperature by one degree Celsius. The relationship between heat and the temperature change is usually expressed as shown below:

$Q=cm$ Δ $T$