the answer is true because i think its true not 100 percent sure
The have the knowledge of a monkey, they survive like monkey, they become one with monkey okay seriously tho they probably have survival knowledge
Answer:

Explanation:
It is given that,
The coordinates of a particle in the metric xy-plane are differentiable functions of time t are given by :


Let D is the distance from the origin. It is given by :

Differentiate above equation wrt t as:

.............(1)
The points are given as, (12,5). Calculating D from these points as :

Put all values in equation (1) as :


So, the particle is moving away from the origin at the rate of 7.076 m/s. Hence, this is the required solution.
The volume of the balloon is given by:
V = 4πr³/3
V = volume, r = radius
Differentiate both sides with respect to time t:
dV/dt = 4πr²(dr/dt)
Isolate dr/dt:
dr/dt = (dV/dt)/(4πr²)
Given values:
dV/dt = 72ft³/min
r = 3ft
Plug in and solve for dr/dt:
dr/dt = 72/(4π(3)²)
dr/dt = 0.64ft/min
The radius is increasing at a rate of 0.64ft/min
The surface area of the balloon is given by:
A = 4πr²
A = surface area, r = radius
Differentiate both sides with respect to time t:
dA/dt = 8πr(dr/dt)
Given values:
r = 3ft
dr/dt = 0.64ft/min
Plug in and solve for dA/dt:
dA/dt = 8π(3)(0.64)
dA/dt = 48.25ft²/min
The surface area is changing at a rate of 48.25ft²/min
Speed=distance/time
=20m/0.5s
=40ms^-1