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TiliK225 [7]
3 years ago
8

Increase in Space Suit Pressure 0.0/3.0 points (graded) If the pressure in a space suit increases, how will each of the followin

g be affected? Flexilibity will: Increase Decrease Stay the same unanswered The required pre-breathe time will: Increase Decrease Stay the same unanswered The mass of the suit will: Increase Decrease Stay the same
Physics
1 answer:
Art [367]3 years ago
3 0

Answer:

Flexibility Increases

Pre-breathe time decreases

Mass of suit decreases.

Explanation:

Spacesuits are designed for space shuttles when a person goes to explore the galaxy. The spacesuits shuttle era are pressurized at 4.3 pounds per inch. The gas in the suit is 100% of oxygen and there is more oxygen to breathe when the altitude of 10,000 is reached. This will decrease the breathing time and mass of suit.

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If the CD rotates clockwise at 500 rpm (revolutions per minute) while the last song is playing, and then spins down to zero angu
gavmur [86]

Answer:

Explanation:

Given that,

Initial Angular velocity w=500rpm

Converting from rpm to rad/s

1rev =2πrad

1minutes =60secs

500rpm=500rev/mins

w = 500×2π/60

wi=52.36rad/s

The final angular velocity wf=0rad/s

Time to stop is t=2.6sec

We want to find angular acceleration α

Using the equation of angular motion

wf = wi + αt.

0 = 52.36 + 2.6α

-52.36=2.6α

α = -52.36/2.6

α = -20.14rad/s²

The angular acceleration is negative because it is decelerating.

Then, α=20.14rad/s²

8 0
2 years ago
Read 2 more answers
Consider the following three statements: For any electromagnetic radiation, the product of the wavelength and the frequency is a
boyakko [2]

Answer:

The correct answer is B. Statements (i) and (ii) are true.

Explanation:

<u>Fisrt statement:</u>

Electromagnetic radiation such as wave, wavelength λ and oscillation frequency ν are related by a constant, the speed of light. The equation is given by:

c= \lambda \nu

So the first statement is true.

<u>Second statement:</u>

c=\lambda \nu\\c= 3.0 A \times 1.0\times 10^{18} Hz\\c= 3.0\times 10^{-10} m  \times 1.0\times 10^{18} s^{-1}\\c=3\times 10^8 \frac{m}{s}

The value of c in the vacuum is 3×10⁸ m/s. Hence, the second statement is true.

<u>Third statement:</u>

The speed of any electromagnetic radiation is constant regardless the type of radiation.

Hence, the third statement is false.

8 0
2 years ago
Can someone help me with this
yKpoI14uk [10]

bonded pairs of electrons, lone pairs of electrons.

4 0
2 years ago
Parker completed 4 laps around a 400 m track. He ran for a total of 30 mins. What is the
Over [174]

Answer:

Distance: 1600 m Displacement: 0

Explanation:

The distance is because He ran 400 meters 4 times getting 1600 m

4*400=1600

The displacement is 0 because displacement is the total distnce away from the starting point and since he ran laps around the track in the end he ended up in the same spot as last time.

7 0
2 years ago
A lightbulb is rated by the power that it dissipates when connected to a given voltage. For a lightbulb connected to 120 V house
Igoryamba

Answer:

Increases, increases

Explanation:

The current is directly proportional to the voltage and inversely proportional to the resistance. The implication of this is that, whenever the voltage is increased, the current increases simultaneously. On the other hand, if the resistance is increased, the current will decrease accordingly and vice versa.

Recall that power is given by P= V^2/R where;

P= power, V= voltage and R= resistance

We can see that power and resistance are inversely related hence decreasing the resistance increases the power output of the lightbulb.

8 0
2 years ago
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