The specific heat, c is 0.75 J/g°C
<u>Explanation:</u>
Heat or Energy, Q = 1500J
Mass, m = 50g
T1 = 0°C
T2 = 40°C
Specific Heat, c = ?
We know,
Q = mcΔT
Q = mc(T2-T1)
1500 = 50 X c X (40-0)
1500 = 50 X c X 40
c = 1500/ 2000
c = 0.75 J/g°C
Therefore, the specific heat, c is 0.75 J/g°C
<h3>
Answer:</h3>
266.325 g
<h3>
Explanation:</h3>
We are given the balanced equation;
2NaOH + H₂SO₄ → H₂O + Na₂SO₄
We are required to determine the mass of Na₂SO₄ that will be formed.
<h3>Step 1: Determine the number of moles of NaOH</h3>
Moles = Mass ÷ molar mass
Molar mass of NaOH is 40.0 g/mol
Therefore;
Moles of NaOH = 150 g ÷ 40 g/mol
= 3.75 moles
<h3>Step 2: Determine the number of moles of sodium sulfate formed</h3>
- From the equation 2 moles of NaOH reacts with sulfuric acid to form 1 mole of sodium sulfate.
- Therefore; mole ratio of NaOH : Na₂SO₄ is 2 : 1
Thus, moles of Na₂SO₄ = Moles of NaOH ÷ 2
= 3.75 moles ÷ 2
= 1.875 moles
<h3>Step 3: Determine the mass of Na₂SO₄ produced.</h3>
we know that;
Mass = Moles × Molar mass
Molar mass of Na₂SO₄ is 142.04 g/mol
Therefore;
Mass of Na₂SO₄ = 1.875 moles × 142.04 g/mol
= 266.325 g
Thus, the mass of sodium sulfate formed 266.325 g
Answer:
B. Contains more matter
Explanation:
The answer is C because it makes sense to me and a golf ball does contain more matter than a tennis ball
Sorry if I'm wrong :(
Answer:
P= 7.01 atm
P(CO₂)= 2.34 atm
Explanation:
Step 1: Convert the temperature to Kelvin
We will use the following expression.
K = °C + 273.15
K = 32.0°C + 273.15 = 305.2 K
Step 2: Calculate the total number of moles of the mixture
We will use the following expression.
n = nCO₂ + nN₂ = 2.33 mol + 4.66 mol = 6.99 mol
Step 3: Calculate the total pressure of the mixture
We will use the ideal gas equation.
P × V = n × R × T
P = n × R × T / V
P = 6.99 mol × 0.0821 atm.L/mol.K × 305.2 K / 25.0 L
P= 7.01 atm
Step 4: Calculate the partial pressure of carbon dioxide
We will use the ideal gas equation.
P(CO₂) × V = nCO₂ × R × T
P(CO₂) = nCO₂ × R × T / V
P(CO₂) = 2.33 mol × 0.0821 atm.L/mol.K × 305.2 K / 25.0 L
P(CO₂)= 2.34 atm
Answer:
D. CH₄(g) + H₂O(g) → CO(g) + 3H₂(g)
Explanation:
A rule of thumb is that there's an increase in entropy if there are more molecules in the products than in the reactants when there's no state change. The only given option where that takes place is option D., as there are two molecules in the reactants and 4 (1 of CO and 3 of H₂) in the products.
