Answer:
Molar mass of bromine is equal to
Explanation:
The molar mass of HBr is equal to the sum of atomic weight of Bromine.
Atomic Weight of hydrogen is equal to
Atomic Weight of Bromine is equal to
Molar mass of Bromine
= Atomic Weight of hydrogen + Atomic Weight of Bromine
Molar mass of Bromine
Answer:
1,812 wt%
Explanation:
The reactions for this titration are:
2Ce⁴⁺ + 3I⁻ → 2Ce³⁺ + I₃⁻
I₃⁻ + 2S₂O₃⁻ → 3I⁻ + S₄O₆²⁻
The moles in the end point of S₂O₃⁻ are:
0,01302L×0,03428M Na₂S₂O₃ = 4,463x10⁻⁴ moles of S₂O₃⁻. As 2 moles of S₂O₃⁻ react with 1 mole of I₃⁻, the moles of I₃⁻ are:
4,463x10⁻⁴ moles of S₂O₃⁻× = 2,2315x10⁻⁴ moles of I₃⁻
As 2 moles of Ce⁴⁺ produce 1 mole of I₃⁻, the moles of Ce⁴⁺ are:
2,2315x10⁻⁴ moles of I₃⁻× = 4,463x10⁻⁴ moles of Ce(IV). These moles are:
4,463x10⁻⁴ moles of Ce(IV)× = <em>0,0625 g of Ce(IV)</em>
As the sample has a 3,452g, the weight percent is:
0,0625g of Ce(IV) / 3,452g × 100 = <em>1,812 wt%</em>
I hope it helps!
Answer:
290 grams
Explanation:
Let's begin by writing the balanced chemical equations:
Then we calculate the number of moles in 97g of propane.
n(propane)=
According to the balanced chemical equation, one mole of propane produces 3 moles of carbon dioxide. So the available number of moles of propane must be multiplied by three to work out the number of carbon dioxide produced.
n(carbon dioxide)= 2.1995mol*3 = 6.5985mol
mass(carbon dioxide) = moles * molar mass
= 6.5985 mol * 44.01 g/mol
= 290 grams