All categories

3 years ago

Please help! Which interval describes where the graph of the function is positive?

Mathematics

1 answer:

cricket20 [7]3 years ago

3 0

Answer:

c. -oo < x < -1

Step-by-step explanation:

according to the graph the function possitive

=> y > 0 , and x < -1

You might be interested in

Coefficient x^2 in the expansion of (2+x)^5

Monica [59]

Alright, expand the given equation:
(2+x) (2+x) (2+x) (2+x) (2+x)
Use FOIL method and distribution to solve
At the final answer, find the x^2 and the number that multiplies to it is the coefficient
I can't do the actually expansion for you, it would take a decently long time. You should be able to, its a good practice. Good luck!

7 0

3 years ago

A sphere has a decimeter of 12 ft what is the volume of the sphere? Give the exact value in terms of

meriva

Answer: 904.78 cu. ft

Step-by-step explanation:

Volume of sphere = 4/3 pi r^3

Assuming 12 ft. is the diameter of the sphere.

6 0

3 years ago

Evaluate 5+5*5+5/5-5+5*5

rewona [7]

Answer:

Step-by-step explanation:

5*5=25

5/5=1

5+25+1-5+25

30+1-5+25

31-5+25

26+25

4 0

3 years ago

Read 2 more answers

Find the quotient of 2.632 · 104 and 2 · 10-7.

faust18 [17]

2.632 x 10^4 ÷ 2 x 10-7 =

1.316 x 10^11

5 0

3 years ago

Read 2 more answers

At a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective pa

11Alexandr11 [23.1K]

Answer:

Probability that fewer than 2 of these parts are defective is 0.604.

Step-by-step explanation:

We are given that at a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective parts 19% of the time.

A random sample of 7 parts produced by this machine is chosen.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 7 parts

r = number of success = fewer than 2

p = probability of success which in our question is % of defective

parts produced by one of the machine, i.e; 19%

LET X = Number of parts that are defective

So, it means X ~ Binom(n = 7, p = 0.19)

Now, probability that fewer than 2 of these parts are defective is given by = P(X < 2)

P(X < 2) = P(X = 0) + P(X = 1)

= $\binom{7}{0}\times 0.19^{0} \times (1-0.19)^{7-0}+ \binom{7}{1}\times 0.19^{1} \times (1-0.19)^{7-1}$

= $1 \times 1 \times 0.81^{7} +7 \times 01.9^{1} \times 0.81^{6}$

= 0.604

Therefore, the probability that fewer than 2 of these parts are defective is 0.604.

8 0

2 years ago