Answer:
B.)
Explanation:
Gains PE and loses ke
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Answer:
220.9g of water are required
Explanation:
The molar enthalpy of vaporization is defined as the heat released when 1 mole of water changes from liquid to gas.
For water, 1 mole releases 40.79kJ. To release 500kJ are necessaries:
500kJ * (1mol / 40.79kJ) = 12.26 moles are necessaries
To convert moles to grams we must use the molar mass (H2O = 18.02g/mol):
12.26 moles * (18.02g / 1 mol) =
<h3>220.9g of water are required</h3>
Answer:
6.286 L.
Explanation:
Applying Charles Law,
V/T = V'/T'............................... Equation 1
Where V = Initial volume of the balloon, T = Initial Temperature of the balloon, V' = Final volume of the balloon, T' = Final Temperature of the balloon
make V' the subject of the equation
V' = VT'/T............................ Equation 2
Given: V = 6.50 L, T = 31 °C = (273+31) K = 304 K, T' = 21 °C = (273+21) K = 294 K
Substitute into equation 2
V' = 6.5(294)/304
V' = 6.286 L.
Hence the new volume in the balloon = 6.286 L.
What does the lab say because then i can help :)
Answer:
Probably around 6 because the ph of hydrochloric acid is 3
Explanation:
