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V125BC [204]
3 years ago
8

Which model of the atom was used as a result of JJ Thomson's cathode ray

Chemistry
1 answer:
mariarad [96]3 years ago
6 0

Answer:

a. Plum pudding model

Explanation:

The plum pudding model of the atom was proposed by J.J. Thomson. It was the model he derived from his experiment on the gas discharge tube.

J.J Thomson was the first person to discover electrons which he called cathode rays because in the discharge tube, they emanate from the cathode.

  • This led him to suggest the plum pudding model of the atom.
  • The model reflects electrons being surrounded by a volume of negative charges.
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Draw structures from the following names, and determine which compounds are optically active:(c) 1,2-dibromo-2-methylbutane
dolphi86 [110]

The given compound 1,2-dibromo-2-methylbutane is an optically active compound .

Because this compound does not have plane of symmetry (POS) and center  of symmetry (COS) i.e. does not have di-symmetry . And also forms non superimposable mirror image . the compound is optically active .

It has  chiral center.

Here , the chiral carbon is attached to the 4 distinct groups such as :  methyl , ethyl , bromine , bromomethane .

<h3>What is di-symmetry?</h3>

Di-symmetry is that which have no center of symmetry and plane of symmetry and alternate axis of symmetry .

<h3>Chiral center :</h3>

Have Sp3 hybridized center (4sigma bond ) .

4 distinct group  is attached to the chiral atom. form non -superimposable mirror image .

<h3>What is optical isomerism ?</h3>

Same molecular formula and same structural formula . also have same physical and chemical properties .

They differ in their behavior towards plane polarized light (ppl) .

Learn more about chiral center here:

brainly.com/question/9522537

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8 0
1 year ago
A Wisconsin farmer taps a maple tree and collects 200 liters of sap. He determines the sucrose (C12H2011) concentration to be 0.
Minchanka [31]

Answer:

6.0 L

Explanation:

Use the dilution equation M1V1 = M2V2

M1 = 0.075 M

V1 = 200 L

M2 = 2.5 M

V2 = ?

Solve for V2 --> V2 = M1V1/M2

V2 = (0.075 M)(200 L) / (2.5 M) = 6.0 L

4 0
2 years ago
Question 21
Mumz [18]
There are 2 moles of O stones present in 88 grams of CO2. Why? Well, we can find the amount of moles present in 88 grams of CO2 by dividing the mass by the molar mass. The mass of CO2 comes out to be 88 grams. The molar mass of CO2 comes out to be 44 grams. Because 88 is the mass of CO2 and 44 is the molar mass of CO2, we can divide 88 by 44 to identify that there are 2.0 moles of O atoms present in 88 grams of CO2.

Your final answer: There are 2.0 moles of O atoms present in 88 grams of CO2. Your final answer to this question is D, or 2.0 moles. If you need to better understand, let me know and I will gladly assist you.
5 0
2 years ago
When solutions of magnesium chloride and potassium phosphate are combined write the formula for the precipitate formed
Zielflug [23.3K]
The products will be magnesium phosphate and potassium chloride. You then have to watch a solubility chart to see which one of these is not soluable. In this case it is magnesium phosphate.
6 0
3 years ago
What accommodations have been designed to protect astronauts from micrometeoroids hitting their spacesuits?
PolarNik [594]

Answer:

They are multilayered

Spacesuits provide protection from radiation and offer normal air pressure inside

Explanation:

3 0
2 years ago
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