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4 years ago

J’ai besoin d’aide pour cette question. Je vais mettre branliest.

Mathematics

1 answer:

Vilka [71]4 years ago

6 0

Reponse:

Pour la mere, la variable independente est l'heure de se coucher. Les resultats scolaires sont la variable dependente.

Pour Tania, c'est le contraire. La variable independente est les resultats scolaires, et la variable dependente est l'heure de se coucher.

You might be interested in

4.8 as an improper fraction

bixtya [17]

.8= 8/10
8/10= 4/5 (reduced)
4 4/5= 24/5

hope this helps

5 0

3 years ago

Which property justifies the following statement?

olya-2409 [2.1K]

In the above question 13m=156 we are dividing both sides by 13 so that m=12 .As $\frac{156}{13} =12$

According to Division property of Equality: If you divide one side of an equation by a number, you also must divide the other side by the same number so that your equation stays the same.

The property Division Property of Equality is justified .

3 0

3 years ago

A sign is being made from a rectangular board of wood that originally measures 36 inches by

lozanna [386]

<h3>Solution (a):</h3>

Area of rectangle = LB
=> Area of rectangle = 18 x 36
=> Area of rectangle = 648 in²

<h3></h3><h3>Solution (b):</h3>

<u>Since the two triangles are equal (as said in the question):</u>

=> Area of triangles: 2(1/2 x 6 x 18)
=> Area of triangles: 6 x 18
=> Area of triangles: 108 in²

<h3 /><h3>Solution (c):</h3>

<u>Subtract the area of the triangles from the area of the rectangle.</u>

648 - 108 = Area of trapezoid
=> 540 in² = Area of trapezoid

7 0

3 years ago

Part 1: Create a scenario for an arithmetic sequence. For example, Jasmine practices the piano for ______ minutes on Monday. Eve

mr Goodwill [35]

Let $a_n$ be the n'th term of a sequence,

for example $a_1$ is the first term, $a_2$ is the second term and so on.
----------------------------------------------------------------------------------------------------
a sequence is arithmetic if the difference between any 2 terms is equal:

so an arithmetic sequence, for the first term = t, and the common difference = d, has the following form:

$a_1=t$

$a_2=t+d$

$a_3=t+d+d$

$a_4=t+d+d+d$

so clearly $a_n=t+d*(n-1)$
---------------------------------------------------------------------------------------------------
A sequence is geometric, if the ratio between any 2 consecutive terms is the same, and it is called the common ratio.

a geometric ratio with first term = t, and common ratio = r is:

$a_1=t$

$a_2=t*r$

$a_3=t*r*r$

$a_4=t*r*r*r$

thus clearly $a_n=t* r^{n-1}$
--------------------------------------------------------------------------------------------------

Part 1:

"<span>Jasmine practices the piano for __30___ minutes on Monday. Every day she ____increases_______ her practice time by ____5 minutes_____. </span>"

let $a_n$ be the number of hours Jasmine practices the n'th day,

for n=7, t=30, d=5 we have

$a_7=30+5*(7-1)=30+5*6=30+30=60$ ,

minutes is the time Jasmine practices on the 7the day.

Part 2

"<span>Anthony goes to the gym for ___60___ minutes on Monday. Every day he ___increases______his gym time by ____1/10_of the previous day_____. </span>"

if $S_n$ represents the minutes that Anthony goes to gym on the n'th day,

then

$S_1=60$

$S_2=60+1/10*60=10/10*60+1/10*60=11/10*60=1.1*60$

$S_3=1.1*1.1*60$

$S_4=1.1*1.1*1.1*60$

$S_5=1.1*1.1*1.1*1.1*60= (1.1)^{4}*60= 1.4641*60=87.85$
(minutes)

Part 3: it is clear that the formula that can be derived in Part 2 is:

$S_n=60*(1.1)^{n-1}$

so assume we want to find how many hours does Anthony spend in the gym on the 10th day,

then we calculate $S_10=60*(1.1)^{9}=60*2.358=141.5$ (minutes)

6 0

3 years ago

Need some help with indefinite integrals pleasee

goldenfox [79]

Observe that $(x^2+2x+2)'=2x+2$ .

You have that $\int \frac{2x}{x^2+2x+2}\; dx=\int \frac{2x+2-2}{x^2+2x+2}\; dx=\int \frac{2x+2}{x^2+2x+2}\; dx+\int \frac{1}{x^2+2x+2}\; dx=I_1+2I_2$ .

To compute $I_1$ you set $y=x^2+2x+2$ , so $dy=2x+2\; dx$ . Therefore, $I_1=\int \frac{1}{y}\; dy=\ln |y|=\ln |x^2+2x+2|=\ln (x^2+2x+2)$ .

For $I_2$ observe that $x^2+2x+2=(x+1)^2+1$ . Let $y=x+1$ . Then $dy=dx$ and $I_2=\int \frac{1}{y^2+1}=\arctan y=\arctan (x+1)$ .

So, $\int \frac{2x}{x^2+2x+2}=\ln (x^2+2x+2)+2\arctan (x+1)+c$ .

8 0

4 years ago