First convert the 590.0 grams of water to liters of water.
590.0 grams x (1 L / 1000 grams) = 0.59 L
Since we're dealing with concentration, recall this formula:
Molarity (M) = (moles of solute) / (liters of solution)
We know the Molarity and the Liters
0.82 M = (moles) / 0.59 L
To find the moles multiply 0.59 on both sides.
The result is 0.4838 moles of CaCl (the solute).
Then change moles into grams because the question wants grams.
In order to convert the moles of a substance to grams, you will need to multiply the mole value of the substance by its molar mass which is 110.986.
(0.4838 moles CaCl2) x (110.986 g CaCl)/ 1 mol CaCl2
<h2><u>
= 53.7g CaCl</u></h2>
<u></u>
<u />
Copper chloride ...............
This problem can be solved by Dalton's law of partial pressures which states that <em>in a mixture of non-reacting gases, the total pressure exerted is equal to the sum of the partial pressures of the individual gases</em>.
Ptotal = P₁ + P₂ + P₃ + ..... + Pn
Herein, Ptotal = P(Ne) + P(Ar) + P(He)
Ptotal = 1.25 atm, P(Ne) = 0.68 atm and P(Ar) = 0.35
So, P(He) = Ptotal - P(Ne) - P(Ar) = 1.25 - 0.68 - 0.35 = 0.22 atm
2Na^+ and S^2-
(sodium cation and sulfide anion)