Ignition transformer
1.
Weight of the transformer is more.
2.
Voltage output of the transformer is from 10,000 volts
to 14,000 volts.
3.
Due to lower voltage output, fuel vaporization and
ignition will be slow.
4.
When there is a drop in voltage supply, the transformer
gets affected.
5.
Consumption of electricity is more.
Solid state igniter.
1.
Igniter weighs very light
2.
Igniter giver voltage output in the range of 14,000
volts to 20,000 volts
3.
Higher voltage output leads to faster vaporization of
fuel and ignition
4.
Very small affect is observed when there is a voltage
drop.
5.
Less electricity is consumed.
Answer:
Detail is given below
Explanation:
Atomic radii trend along group:
As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.
As the size of atom increases the ionization energy from top to bottom also decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.
In A we can see that there is one positive charge and force of attraction is 2.30×10⁻⁸ N and distance is 0.10 nm
In B we can see that negative charge is further away from nucleus because of greater distance thus force of attraction will be less. 0.58×10⁻⁸ N
In C this distance further increases and force also goes in decreasing 0.26×10⁻⁸ N.
Answer:
V = 0.5 L
Explanation:
Given data:
Moles of nitrogen = 2.23×10⁻² mol (0.0223 mol)
Temperature = 273 K
Pressure = 1 atm
Volume = ?
Solution:
PV = nRT
V = nRT / P
V = 0.0223 mol × 0.0821 atm. mol⁻¹. L . k⁻¹ × 273 K / 1 atm
V = 0.5 L
BaCl₂(aq) + Na₂SO₄(aq) = BaSO₄(s) + 2NaCl(aq)
Ba²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq) = BaSO₄(s) + 2Na⁺(aq) + 2Cl⁻(aq)
Ba²⁺(aq) + SO₄²⁻(aq)= BaSO₄(s)
