All categories

3 years ago

What is the most common isotope for element X

Chemistry

1 answer:

ankoles [38]3 years ago

5 0

Answer:

isotope 2

Explanation:

it has the highest percentage abundance

You might be interested in

In which situation is no work considered to be done by a force?

Masja [62]

If the angle is either 0 or 180, that means that there is either negative or positive work, so A and D are not correct.

If the angle is 45, then there is still some work involved.

The only option where there is no work done by a force is B. when the angle is between the force and displacement is 90.

7 0

3 years ago

Read 2 more answers

If you have a density of 100 kg/L and a mass of 1000 g what is the volume (please explain)

olchik [2.2K]

Answer: Volume = 0.01L

Explanation:

The density of a substance is given by; Density = Mass / Volume.

In this question, Mass = 1000g, Volume = ? and Density = 100 Kg/L

For the units to be uniform, we convert 1000g to Kg = 1Kg

Therefore, Volume = Mass / Density = 1Kg / 100Kg/L = 0.01L

6 0

3 years ago

The individual components of a solution_____.

Misha Larkins [42]

Its been awhile since I've dabbled in chemistry, but i do know that A isnt the answer because the question says solution, not mixture. This looks somewhat like a trick question, it says individual components, so the answer would be C. This is because the individual components do react to form a compound. B and D would be true if it didnt say individual components, so the question is basically focusing on only one ingredient, not the whole solution. Answer: C

4 0

3 years ago

Read 2 more answers

HELPPPP. SHOW WORK

nekit [7.7K]

I think The answer to two is it would sink

7 0

3 years ago

Write the oxidation and reduction half reactions;

luda_lava [24]

Answer:

$Fe^{2+}$ ⇒ $Fe^{3+}+e^-$

$Br_2+2e^-$ ⇒ $2Br^-$

$Mg$ ⇒ $Mg^{2+}+2e^-$

$Cr^{3+}+e^-$ ⇒ $Cr^{3+}$

Explanation:

Remember that positive number superscripts mean electrons lack and negative numbers mean electrons 'excess' (if we compare it with the neutral element). So, for the case of Fe2+ which is converted to Fe3+, we know that in Fe2+ there is a two electrons lack, while in Fe3+ there is a 3 electrons lack; it means that Fe2+ was converted to Fe3+ but releasing one electron:

$Fe^{2+}$ ⇒ $Fe^{3+}+e^-$

The same analysis is applied to Br2; Br2 is a molecule which is said to have a zero superscript because it is an apolar covalent bond; and it is converted to Br-, which, according to what I wrote above, means that there is a one electron excess. So, Br2 must have received an electron in order to change to Br-; but Br2 can't change to Br- as simple as that because Br2 is a molecule, not an atom; it is a molecule that has two Br atoms, so, Br2 must give two Br- ions as products, but receiving one electron for each one:

$Br_2+2e^-$ ⇒ $2Br^-$

Applying the same, in Mg2+ there is a 2 electrons lack, and in Mg is not electron lack (its superscript is zero), so Mg must have released two electrons in order to change to Mg2+:

$Mg$ ⇒ $Mg^{2+}+2e^-$

Cr3+ has a 3 electrons lack, and Cr2+ a two electrons one, so, Cr3+ must receive an electron to convert to Cr2+:

$Cr^{3+}+e^-$ ⇒ $Cr^{3+}$

3 0

4 years ago

Read 2 more answers