Answer:
281s
Explanation:
Given parameters:
Speed of the scooter = 1.45min per mile
Fuel economy of engine = 85miles per gallon
Quantity of fuel = 145mL
Unknown:
Time of travel with the volume of fuel given = ?
Solution:
To solve this problem, we need to find the distance the fuel will last.
Rate of fuel consumption by the engine = 85miles per gallon
Convert 145mL to gallons;
3785.41mL = 1 gallon
145mL will therefore give 
= 0.038gallons
So;
Distance covered = 85miles per gallon x 0.038gallons = 3.23miles
From;
Rate of travel = 
Time = rate of travel x distance = 1.45 minutes per mile x 3.23miles
Time = 4.7min
1 min = 60s
4.7min = 4.7 x 60 = 281s
Hello there.
<span>A 250.0 ml buffer solution is 0.250 M in acetic acid and. 250M in sodium acetate. what is the ph after addition of. 0050 mol of HCL? what is the ph after the addition of. 0050 mol of NaOH?
Part 2 answer: </span><span>pH = 4.67 </span>
K₃PO₄ → 3K⁺ + PO₄³⁻
PO₄³⁻ + H₂O ⇄ HPO₄²⁻ + OH⁻
HPO₄²⁻ + H₂O ⇄ H₂PO₄⁻ + OH⁻
H₂PO₄⁻ + H₂O ⇄ H₃PO₄ + OH⁻
K⁺, PO₄³⁻, HPO₄²⁻, H₂PO₄⁻, OH⁻
Solution:
Using Ideal Gas law:
P1 = 1.45 atm
V1 = 5.15 L
P2 = ?
V2 = 3.43 L
Using Ideal Gas Law, PV = nRT:
Now, the number of moles (n) is the same independent of pressure and distance, so let's say that the temperature is stable since there is no details on the issue. As a consequence,
P1V1 = nRT = P2V2
P1V1 = P2V2
Solve for P2 and you're going to get 2.03 atm. It makes sense as you decrease the amount of the gas by compressing it, which implies that you raise the heat.
2) P = 1.5 atm
T = 301 K
n = 0.785 moles
PV = nRT
V = nRT/P
R = 0.0821 (L*atm)/(mol * K)
Therefore,
V = (0.785 * 0.0821 * 301)/1.5 = 19.4 L
