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FrozenT [24]
4 years ago
9

What is the density of an object that has a mass of 6.5 g and when placed in water displaces the volume from 4.5mL to 11.8mL? ro

und to the nearest tenth
Chemistry
1 answer:
KengaRu [80]4 years ago
3 0

Answer:

\rho =0.9g/mL

Explanation:

Hello,

In this case, due to the volume displacement caused the by the object's submersion, it's volume is:

V=11.8mL-4.5mL=7.3 mL

In such a way, considering the mathematical definition of density, it turns out:

\rho =\frac{m}{V}=\frac{6.5g}{7.3mL}\\  \\\rho =0.89g/mL

Rounding to the nearest tenth we finally obtain:

\rho =0.9g/mL

Regards.

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I know the correct answer is either a or d. Can anyone explain which one it is and why? CH3C ≡ CCH2CH2Cl is named: a. 1-chloro-3
lara31 [8.8K]

Answer:

D.

Explanation:

CH₃C≡ CCH₂CH₂Cl

Since there are 5 carbons so the suffix used is "pent"

There is a triple bond so its alkyne

So the compound becomes 2-pentyne (2 because the triple bond is with the 2nd carbon)

Then,

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3 years ago
5. A shiny, gold-colored bar of metal weighing 57.3 g has a volume of 4.7 cm 3 . Is the bar of metal pure
agasfer [191]

1. The bar of metal is not pure gold.

2. The volume of 50.0 g of air is 42,016 mL.

3. The mass of the pure aluminum is 135 g.

4. The light beam's wavelength in meters is 475 x  10^{-9 m.

<h3>What is density?</h3>

The density of a substance is the ratio of the mass of the substance and its volume.

Density = mass/volume.

For the first problem: mass = 57.3 g, volume = 4.7 cm3

Density of the metal = 57.3/4.7

                                   = 12.19 g/cm3

The density of gold is 19.3 g/cm3. Thus, the bar of metal is not pure gold.

For the second problem: density = 1.19 x 10^{-3 g/ml, mass = 50.0 g

Volume = mass/density

                 = 50/1.19 x 10^{-3

                      = 42,016 ml

The volume of 50.0 g of air is 42,016 mL.

For the third problem: density = 2.70 g/ml, volume = 50.0 ml.

Mass = density x volume

                 = 2.70 x 50

                       = 135 g

The mass of the pure aluminum is 135 g.

Lastly:

nano = 10^{-9

475 nm = 475 x  10^{-9 m

The light beam's wavelength in meters is 475 x  10^{-9 m.

More on density can be found here: brainly.com/question/15164682

#SPJ1

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