Answer:
Wavelength, ![\lambda=3.01\ m](https://tex.z-dn.net/?f=%5Clambda%3D3.01%5C%20m)
Explanation:
It is given that,
Frequency, f = 99.5 MHz = 99.5 × 10⁶ Hz
We need to find the wavelength of the radio waves from an FM station operating at above frequency. The relationship between the frequency and the wavelength is given by :
![c=f\lambda](https://tex.z-dn.net/?f=c%3Df%5Clambda)
![\lambda=\dfrac{c}{f}{](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7Bc%7D%7Bf%7D%7B)
c = speed of light
![\lambda=\dfrac{3\times 10^8\ m/s}{99.5\times 10^6\ Hz}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B3%5Ctimes%2010%5E8%5C%20m%2Fs%7D%7B99.5%5Ctimes%2010%5E6%5C%20Hz%7D)
![\lambda=3.01\ m](https://tex.z-dn.net/?f=%5Clambda%3D3.01%5C%20m)
So, the wavelength of the radio waves from an FM station is 3.01 m. Hence, this is the required solution.
A. Blocking light waves that vibrate in the plane. (?)
Answer:
Venus
Explanation:
To know the correct answer to the question, we shall determine the weight of the space probe on each planet to see which will correspond to 3560 N.
This is illustrated below:
For Mercury:
Mass = 400 Kg
Gravitational force = 3.7 N/Kg
Weight =?
Weight = mass × gravitational force
Weight = 400 × 3.7
Weight = 1480 N
For Venus:
Mass = 400 Kg
Gravitational force = 8.9 N/Kg
Weight =?
Weight = mass × gravitational force
Weight = 400 × 8.9
Weight = 3560 N
For Earth:
Mass = 400 Kg
Gravitational force = 9.8 N/Kg
Weight =?
Weight = mass × gravitational force
Weight = 400 × 9.8
Weight = 3920 N
For Neptune:
Mass = 400 Kg
Gravitational force = 11 N/Kg
Weight =?
Weight = mass × gravitational force
Weight = 400 × 11
Weight = 4400 N
For Jupiter:
Mass = 400 Kg
Gravitational force = 23.1 N/Kg
Weight =?
Weight = mass × gravitational force
Weight = 400 × 23.1
Weight = 9240 N
SUMMARY:
Planet >>>>>> Weight
Mercury >>>> 1480 N
Venus >>>>>> 3560 N
Earth >>>>>>> 3920 N
Neptune >>>> 4400 N
Jupiter >>>>>> 9240 N
From the above calculations, we can see that the weight of the space probe (i.e 3560 N) correspond to the weight on venus (i.e 3560 N)
Answer:
The answer to the questions is;
In terms of standing waves, the listener moves from a location with high amplitude to one with lower amplitude or vibration (anti-node to node)
The distance 4.1 cm is equivalent to λ/4
Explanation:
For standing waves we have is a stationary wave comprising of two opposite direction moving waves that have equal amplitude and frequency, resulting in the superimposition of the waves. As such certain points are fixed along the wave path that is the peaks amplitude of the wave oscillation is constant at a particular point. A node occurring at a point and an anti-node occurring at another fixed point
When the listener moves 4.1 cm he or she has left the anti-node to the node hence the faintness of the sound
The distance from the node to the anti-node is 1/4 wavelength, or 1/4×λ
Therefore 4.1 cm is λ/4
Answer:
B
Explanation:
Fermium is a synthetic element with the symbol Fm and atomic number 100. It is an actinide and the heaviest element that can be formed by neutron bombardment of lighter elements, and hence the last element that can be prepared in macroscopic quantities, although pure fermium metal has not yet been prepared.[3] A total of 19 isotopes are known, with 257Fm being the longest-lived with a half-life of 100.5 days.
It was discovered in the debris of the first hydrogen bomb explosion in 1952, and named after Enrico Fermi, one of the pioneers of nuclear physics. Its chemistry is typical for the late actinides, with a preponderance of the +3 oxidation state but also an accessible +2 oxidation state. Owing to the small amounts of produced fermium and all of its isotopes having relatively short half-lives, there are currently no uses for it outside basic scientific research.