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3 years ago

A 400-kg space probe has a weight of 3,560 N on one of the above planets. According to the table

Physics

1 answer:

Rzqust [24]3 years ago

8 0

Answer:

Venus

Explanation:

To know the correct answer to the question, we shall determine the weight of the space probe on each planet to see which will correspond to 3560 N.

This is illustrated below:

For Mercury:

Mass = 400 Kg

Gravitational force = 3.7 N/Kg

Weight =?

Weight = mass × gravitational force

Weight = 400 × 3.7

Weight = 1480 N

For Venus:

Mass = 400 Kg

Gravitational force = 8.9 N/Kg

Weight =?

Weight = mass × gravitational force

Weight = 400 × 8.9

Weight = 3560 N

For Earth:

Mass = 400 Kg

Gravitational force = 9.8 N/Kg

Weight =?

Weight = mass × gravitational force

Weight = 400 × 9.8

Weight = 3920 N

For Neptune:

Mass = 400 Kg

Gravitational force = 11 N/Kg

Weight =?

Weight = mass × gravitational force

Weight = 400 × 11

Weight = 4400 N

For Jupiter:

Mass = 400 Kg

Gravitational force = 23.1 N/Kg

Weight =?

Weight = mass × gravitational force

Weight = 400 × 23.1

Weight = 9240 N

SUMMARY:

Planet >>>>>> Weight

Mercury >>>> 1480 N

Venus >>>>>> 3560 N

Earth >>>>>>> 3920 N

Neptune >>>> 4400 N

Jupiter >>>>>> 9240 N

From the above calculations, we can see that the weight of the space probe (i.e 3560 N) correspond to the weight on venus (i.e 3560 N)

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Tamiku [17]

Gravitational Potential Energy, GPE = mgh

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The only value that be controlled here is the height h. The mass is constant, and acceleration due to gravity at that place is constant.

But h can be varied.

Hence to increase the gravitational potential energy between yourself and Earth is to increase the height h.

This can be done by climbing up a table, or climbing up a building through the stairs, or by using a lift.

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3 years ago

A person hangs from a nylon rope (Young's modulus of 5 x 109 N/m2) as seen in the picture below. The rope stretches by 2 % and h

disa [49]

Answer:

959183.7 kg

Explanation:

from the question we have :

young modulus = 5 x 10^{9} N/m^{2}

strain = 2% = 2÷100 = 0.02

diameter = 0.03 m

radius = 0.015 m

acceleration due to gravity (g) = 9.8 m/s^{2}

we can get the mass from the formula below

young modulus = stress ÷ strain

where

stress = \frac[force}{area} = \frac {mass x g}{area}

area = 2πr = 2π x 0.015 = 0.094

therefore

young modulus = \frac{\frac {mass x g}{area}}{strain}

5 x 10^{9} = \frac{\frac {mass x 9.8}{0.094}}{0.02}

mass = \frac{5 x 10^{9} x 0.02 x 0.094}{9.8}

mass = 959183.7 kg

8 0

3 years ago

I need help with this

ra1l [238]

What is that?? Please tell us

5 0

3 years ago

The reaction mixture represented above is at equilibrium at 298 K. The value of the equilibrium constant for the reaction is 16

andre [41]

Answer : The equilibrium concentration of T(g) is 0.5 M

Solution :

Let us assume that the equilibrium reaction be:

The given equilibrium reaction is,

$R(g)+2T(g)\rightleftharpoons 2X(g)+Z(g)$

The expression of $K_c$ will be,

$K_c=\frac{[Z][X]^2}{[R][T]^2}$

where,

$K_c$ = equilibrium constant = 16

[Z] = concentration of Z at equilibrium = 2.0 M

[R] = concentration of R at equilibrium = 2.0 M

[X] = concentration of X at equilibrium = 2.0 M

[T] = concentration of T at equilibrium = ?

Now put all the given values in the above expression, we get:

$16=\frac{(2.0)\times (2.0)^2}{(2.0)\times [T]^2}$

$[T]=0.5M$

Therefore, the equilibrium concentration of T(g) is 0.5 M

8 0

4 years ago

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krok68 [10]

Answer:

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Explanation:

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7 0

3 years ago