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antiseptic1488 [7]
2 years ago
15

Which property increases as an electromagnetic waves energy decreases

Physics
2 answers:
s2008m [1.1K]2 years ago
7 0

Answer:

wavelength

Explanation:

ape x

Rufina [12.5K]2 years ago
3 0

Answer:

Wavelength

Explanation:

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Consider a car moving with a constant velocity of 90 m/s. What is it’s acceleration.
Troyanec [42]

Answer:

Zero

Explanation:

Acceleration is rate of change of velocity..

5 0
3 years ago
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As the frequency of a wave increases the wavelength.
zaharov [31]

Answer:

decreases

Explanation:

Remeber:

There is always inverse relation between frequency and wavelength.

So if one of them increases, other decreases and vice-versa.

f ∝ 1 / λ

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If a 70-kg swimmer pushed off a pool wall with a force of 250N at what rate will the swimmer accelerate from the wall
Vlad [161]
F = ma
250 = 70 x a
a = 250/70
a = 3.57
5 0
3 years ago
Which color of light is diffracted at a greater angle from a diffraction grating, red or yellow light?
topjm [15]
The amount of diffraction depends on the wavelength of light, with shorter wavelengths being diffracted at a greater angle than longer ones (in effect, blue and violet<span> light are diffracted at a larger angle than is red light).

I hope my answer has come to your help. God bless and have a nice day ahead!
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3 0
3 years ago
Heat transfers energy from a hot object to a cold object. Both objects are isolated from their surroundings. The change in entro
aniked [119]

To develop this problem we will start from the definition of entropy as a function of total heat, temperature. This definition is mathematically described as

S = \frac{Q}{T}

Here,

Q = Total Heat

T = Temperature

The total change of entropy from a cold object to a hot object is given by the relationship,

\Delta S = \frac{Q}{T_{cold}}-\frac{Q}{T_{hot}}

From this relationship we can realize that the change in entropy by the second law of thermodynamics will be positive. Therefore the temperature in the hot body will be higher than that of the cold body, this implies that this term will be smaller than the first, and in other words it would imply that the magnitude of the entropy 'of the hot body' will always be less than the entropy 'cold body'

Change in entropy \Delta S_{hot} is smaller than \Delta S_{cold}

Therefore the correct answer is C. Will always have a smaller magnitude than the change in entropy of the cold object

5 0
2 years ago
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