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Masja [62]
3 years ago
5

What is the wavelength of the radio waves from an FM station operating at a frequency of 99.5 MHz

Physics
1 answer:
ser-zykov [4K]3 years ago
3 0

Answer:

Wavelength, \lambda=3.01\ m

Explanation:

It is given that,

Frequency, f = 99.5 MHz = 99.5 × 10⁶ Hz

We need to find the wavelength of the radio waves from an FM station operating at above frequency. The relationship between the frequency and the wavelength is given by :

c=f\lambda

\lambda=\dfrac{c}{f}{

c = speed of light

\lambda=\dfrac{3\times 10^8\ m/s}{99.5\times 10^6\ Hz}

\lambda=3.01\ m

So, the wavelength of the radio waves from an FM station is 3.01 m. Hence, this is the required solution.

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How to calculate depth of sea whan a ship receives sound produced by its fathometer after 3.5 second
HACTEHA [7]

Answer:

2600 m

Explanation:

A fathometer produces a sound wave and then detects the echo.  It takes 3.5 seconds for the echo to reach the ship, so that means it takes half the time (1.75 seconds) to reach the ocean floor.

The speed of sound in seawater is approximately 1500 m/s, so the depth of the ocean at that point is:

d = 1500 m/s × 1.75 s

d = 2625 m

Rounding to two significant figures, the depth is approximately 2600 m.

5 0
3 years ago
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mihalych1998 [28]

Answer:

3

Explanation:

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Direct current made it possible to distribute electric power over greater areas.
Mademuasel [1]
True, I'm not the best when it comes to science, but I'm pretty sure it's this
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2 years ago
I need help in my physics class and show me how it’s done
Korolek [52]

If we have the angle and magnitude of a vector A we can find its Cartesian components using the following formula

A_x = |A|cos(\alpha)\\\\A_y = |A|sin(\alpha)

Where | A | is the magnitude of the vector and \alpha is the angle that it forms with the x axis in the opposite direction to the hands of the clock.

In this problem we know the value of Ax and Ay and we need the angle \alpha.

Vector A is in the 4th quadrant

So:

A_x = 6\\\\A_y = -6.5

So:

|A| = \sqrt{6^2 + (-6.5)^2}\\\\|A| = 8.846

So:

Ay = -6.5 = 8.846cos(\alpha)\\\\sin(\alpha) = \frac{-6.5}{8.846}\\\\sin(\alpha) = -0.7348\\\\\alpha = sin^{- 1}(- 0.7348)

\alpha = -47.28 ° +360° = 313 °

\alpha = 313 °

Option 4.

4 0
3 years ago
A short current element dl⃗ = (0.500 mm)j^ carries a current of 4.80 A in the same direction as dl⃗ . Point P is located at r⃗ =
sammy [17]

Answer:

Magnetic field in Tesla: 1.65*10^−10 T,   0,   3.09*10^−10 T

Explanation:

Given data:

i = 4.8 A ,

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Attached below is the detailed solution

7 0
3 years ago
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