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NeTakaya
3 years ago
15

Determine the slope of the line that passes through the points (8, 0) and (-3, 9)

Mathematics
2 answers:
Leona [35]3 years ago
6 0

Answer:

-9/11

Step-by-step explanation:

The slope of the line is given by

m = (y2-y1)/(x2-x1)

   = (9-0)/(-3-8)

  = 9/-11

  = -9/11

AleksAgata [21]3 years ago
3 0

Answer:

Step-by-step explanation:

First of all, we need to remember what a slope is. This math concept is attached to lines or linear functions which graph is a line. So, a concept that defines lines is its inclination, which is called in math as Slope. So, basically, the slope refers to the amount of inclination of an specific line or linear function, which can be calculated with this equation: m = \frac{y_{2}-y_{1}  }{x_{2}-x_{2}  }

In this case, x_{1} y_{1} refers to the coordinates of the first point: (8,0)

And, x_{2} y_{2} refers to the coordinates of the second point (-3,9)

So, applying all to the equation to find the slope:

m = \frac{y_{2} - y_{1} }{x_{2} - x_{1} } = \frac{9-0}{-3-8} = \frac{9}{-11}

Hence, the slope is m = -\frac{9}{11}

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Given that f(x)=x^2-4x -3 and g(x)=x+3/4 solve for f(g(x)) when x=9
SSSSS [86.1K]

Answer:

f(g(9)) = 945/16

Step-by-step explanation:

To find f(g(x)), you have to substitute g(x) wherever there is an x in f(x).

g(x) = x + 3/4

f(x) = x² - 4x - 3

f(g(x)) = (x + 3/4)² - 4(x + 3/4) - 3

f(g(x)) = x² + 3/2x + 9/16 - 4x + 3 - 3

f(g(x)) = x² - 5/2x + 9/16 + 3 - 3

f(g(x)) = x² - 5/2x + 9/16

Now, put a 9 wherever there is an x in f(g(x)).

f(g(9)) = (9)² - 5/2(9) + 9/16

f(g(9)) = 81 - 5/2(9) + 9/16

f(g(9)) = 81 - 45/2 + 9/16

f(g(9)) = 117/2 + 9/16

f(g(9)) = 945/16

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3 years ago
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