I believe that the answer is B 17
Domain:
This function is a polynomial, i.e. a sum of powers of a variables, each with its coefficient. Polynomials are defined for every possible value of the variable, so the domain is the whole real number set: 
Range:
A polynomial of degree 2 represents a parabola. Since the leading coefficients, i.e. the coefficient of the term with highest degree, is positive (in this case, it's 3), the parabola is concave up. It means that it has a minimum, and it's unbounded from above. So, the range is something like
. To find the minimum, let's start with the "standard" parabola
, and transform it to the one of this exercise.
has minimum 0, and thus its range is
. When you multiply it times three, its shape narrows, but the range wont change:
. Finally, when you subtract 5, you shift everythin down 5 units. This transformation affects the range, since you have 
Image of -3:
To compute
, simply plug
in the formula:

Numbers associated with 43:
We want to see which x value we must choose to get a y value of 43. So, the equation is

Answer:
The answer is 25
Step-by-step explanation:
What I would is to first divide 78 by 3. That will get you 26. Then add one to get 27, subtract one to get 25. 25+26+27=78
The answer is 25.
It would be the second one
Answer:

Step-by-step explanation:
None of your proposed answers has an exponent <em>t</em>.
Here's the logic behind the answer:
Year 0: pop. = 2500
Year 1: pop. = 2500(1.04) That is 104% of the previous year's pop.
Year 2: pop. = 2500(1.04)(1.04) = 2500(1.04)^2
Year 3: pop. = 2500(1.04)^2 x (1.04) = 2500(1.04)^3
See the pattern? The exponent matches the year number.