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allsm [11]
3 years ago
6

A student needs to use the metric system while measuring the length of a box. Which units should he use?

Physics
2 answers:
Andrews [41]3 years ago
8 0
It depends on the size of the box.

-- If it's one of the boxes printed on a sheet of graph paper,
then he should report the measurement in millimeters.

-- If it's the box that his new smartphone arrived in, then
he should probably use centimeters.

-- If it's the box that the new tractor was shipped to his
grandfather's farm in, then meters is the best unit.
Elden [556K]3 years ago
6 0

Answer:

centimeters

Explanation:

I took the test :)

hope this helps! have a good day! :))

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What is the iv and the DV in a rocket​
alekssr [168]

an independent variable (IV) that you can change. • Typical IV's might be number of fins, length of rocket, type of material, mass of the rocket. • Choose one dependent variable (DV) and make three launches per DV for each IV for a total of. six launches..

Explanation:

6 0
3 years ago
A swimming pool heater has to be able to raise the temperature of the 40 000 gallons of water in the pool by 10.0 C°.
alexandr402 [8]

Answer:

b. 1 770 kWh

Explanation:

The heat needed to change the temperature of a certain amount of a substance is given by:

Q=mC\Delta T

Here m is the mass of the susbtance, C is the specific heat of the substance and \Delta T is the temperature change

Q=(40000*3.8kg)(4186\frac{J}{kg\cdot ^\circ C})(10^\circ C)\\Q=6.36*10^9J

Recall that one watt hour is equivalent to 1 watt (1 W) of power sustained for 1 hour. One watt is equal to 1 J/s. So, one watt hour is equal to 3600 J and one kilowatt hour is equal to 3600*10^3 J

Q=6.36*10^9J*\frac{1kW\cdot h}{3600*10^3J}\\Q=1766.66kW\cdot h

6 0
3 years ago
Help ASAP PLEASE THANKS
seraphim [82]

Answer:

a

Explanation:

5 0
3 years ago
Read 2 more answers
Which two quantities can be used to describe motion? A: Displacement and weight. B: speed and acceleration. C: speed and mass. D
HACTEHA [7]
The answer is B as all the other options contain quantities not related to describing motion
3 0
3 years ago
A playground is on the flat roof of a city school, 6.2m above the street below. The vertical wall of the building is h=7.30m hig
olya-2409 [2.1K]

Answer:

a. 18.13m/s

b. 0.84m

c. 2.4m

Explanation:

a. to find the speed at which the ball was lunched, we use the horizontal component.Since the point distance from the base of the ball is 24m and it takes 2.20 secs to reach the wall,we can say that

t=distance /speed

speed v_{x}=vcos\alpha=24/2.2=10.9m/s\\V=10.9/cos53^{0}\\V=18.13m/s

Hence the speed at which ball was lunched is 18.13m/s

b. from the equation

y=v_{y}t-\frac{1}{2}gt^{2}\\ v_{y}=18.13sin53=14.48m/s\\\\y=(14.48*2.2)-\frac{1}{2}9.8*2.2^{2}\\y=8.14m\\

the vertical distance at which the ball clears the wall is

y=8.14-7.3=0.84m

c. the time it takes the ball to reach the 6.2m vertically

6.2=14.47t-4.8t^{2}\\\\14.47t-4.8t^{2}-6.2=0\\\using\\t=-b±\frac{\sqrt{b^{2}-4ac} }{2a}\\ where \\a=-4.8, b=14.47t, c=6.2\\hence t=2.4secs

the horizontal distance covered at this speed is

y+24=(18.13cos53)2.4\\y=26.186-24\\y=2.12m

4 0
3 years ago
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