calcula la potencia por hora de un radiador, sabiendo que esta conectado a un contacto común 110 v. y requiere 20 Amp.
1 answer:
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Answer:
Double the current
Explanation:
The energy delivered by the heater is related to the current by the following relation:
E=
let R * t = k ( ∴ R and t both are constant)
so E= k
Now let:
E2= k I₂^2
E2= 4E
⇒ k I₂^2= 4* k
Cancel same terms on both sides.
I₂^2= 4*
taking square-root on both sides.
√I₂^2 = √4* I^2
⇒I₂= 2I
If we double the current the energy delivered each minute be 4E.
Answer:
Explanation:
<u>Capacitance</u>
A two parallel-plate capacitor has a capacitance of
where
A = area of the plates =
d = separation of the plates
We need to compute C. We'll use the circuit parameters for that. The reactance of a capacitor is given by
where w is the angular frequency
Solving for C
The reactance can be found knowing the total impedance of the circuit:
Where R is the resistance, . Solving for Xc
The magnitude of the impedance is computed as the ratio of the rms voltage and rms current
The rms current is the peak current Ip divided by , thus
Now collect formulas
Or, equivalently
The capacitance is now
The radius of the plates is
The separation between the plates is