1,100 grams :)
you add the grams of both substances and because they're liquid they don't cancel out
Answer:
260 moles of Helium
Explanation:
V = 50L
T = 20°C = (20 + 273.15)K = 293.15K
P = 125 atm
R = 0.082 L.atm / mol. K
n = ?
From ideal gas equation,
PV = nRT
P = pressure of a given gas
V = volume it occupies
n = number of moles
R = ideal gas constant
T = temperature of the gas
PV = nRT
n = PV / RT
n = (125 * 50) / (0.082 * 293.15)
n = 6250 / 24.0383
n = 260.00 moles
The child inhaled 260 moles of Helium
Warm air from above the water rises and is replaced by the cool air from the shore
Answer:
V₂ = 1070 mL or 1.07 L
Solution:
Data Given;
P₁ = 1170 mmHg
V₁ = 915 mL
T₁ = 24 °C + 273 K = 297 K
P₂ = 842 mmHg
V₂ = ?
T₂ = - 23 °C + 273 K = 250 K
According to Ideal gas equation,
P₁ V₁ / T₁ = P₂ V₂ / T₂
Solving for V₂,
V₂ = P₁ V₁ T₂ / P₂ T₁
Putting Values,
V₂ = (1170 mmHg × 915 mL × 250 K) ÷ (842 mmHg × 297 K)
V₂ = 1070 mL or 1.07 L
Answer:
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