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Mama L [17]
3 years ago
5

ch sulfide (ZnS) occurs in the zinc blende crystal structure, (a) If 254 g of ZnS contains 170 g of Zn, what is the mass ratio o

f zinc to surfide? (b) How many kilograms of Zn are in 3.82 kg of ZnS?
Chemistry
1 answer:
Aleonysh [2.5K]3 years ago
8 0

Answer:

The mass ratio of zinc to sulfide is 85:42.

2.5559 kg of Zn are in 3.82 kg of ZnS.

Explanation:

a) Mass of zinc sulfide = 254 g

Mass of zinc in a zinc sulfide sample = 170 g

Mass of sulfide in zinc sulfide sample = x

254 g = 170 g+ x

x = 84 g

The mass ratio of zinc to sulfide:

\frac{170 g}{84 g}=\frac{85}{42}

b) Mass of zincsulfide sample = 3.83 kg

The mass ratio of zinc to sulfide is 85:42.

Let the mass of zinc and sulfide be 85x and 42x respectively:

85 x+ 42 x=3.82 kg

x =0.03007 kg

Mass of an zinc= 85x=85 × 0.03007 kg= 2.5559 kg

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When 2.50 g is burned then in oxygen then 1.25kj of heat is produced.
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Medicinal “ether" is produced when ethyl alcohol is treated with an acid. How many grams of
DochEvi [55]

Answer:

34.3 g

Explanation:

Step 1: Write the balanced equation

2 CH₃CH₂OH ⇒ CH₃CH₂OCH₂CH₃ + H₂O

Step 2: Calculate the moles corresponding to 50.0 g of CH₃CH₂OH

The molar mass of CH₃CH₂OH is 46.07 g/mol.

50.0 g × 1 mol/46.07 g = 1.09 mol

Step 3: Calculate the theoretical moles of CH₃CH₂OCH₂CH₃ produced

The molar ratio of CH₃CH₂OH to CH₃CH₂OCH₂CH₃ is 2:1. The moles of CH₃CH₂OCH₂CH₃ theoretically produced are 1/2 × 1.09 mol = 0.545 mol.

Step 4: Calculate the real moles of CH₃CH₂OCH₂CH₃ produced

The percent yield of the reaction is 85%.

0.545 mol × 85% = 0.463 mol

Step 5: Calculate the mass corresponding to 0.463 moles of CH₃CH₂OCH₂CH₃

The molar mass of CH₃CH₂OCH₂CH₃ is 74.12 g/mol.

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6 0
3 years ago
List the number of each type of atom on the left side of the equation 2C10H22(l)+31O2(g)→20CO2(g)+22H2O(g)
Leokris [45]

<u>Answer:</u>

<em>20, 44, 62 </em>

<em></em>

<u>Explanation:</u>

To find the number of atoms of each element, we multiply coefficient and subscript  

For example 5 Ca_1 Cl_2 contains  

5 × 1 = 5 ,Ca atoms and

5 × 2 = 10, Cl atoms  

If there is a bracket in the chemical formula  

For example 3Ca_3 (P_1 O_4 )_2

we multiply coefficient × subscript × number outside the bracket to find the number of atoms  

(Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So

3 × 3 = 9 , Ca atoms  

3 × 1 × 2 = 6, P atoms  

3 × 4 × 2 = 24, O atoms are present.

So let us find the number of atoms of each element on the left  side of the equation  

2C_{10} H_{22} (l)+31O_2 (g)\Rightarrow 20CO_2 (g)+22H_2 O(g)

Number of C atoms = 2 × 10 = 20

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20, 44, 62  are the Answers.

3 0
3 years ago
How many atoms are in a solid piece of iron that has a mass of 24.0g?
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5 0
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On balancing the number of electrons we get:

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Therefore for 2 moles of Al,

Total (2\times6)F mole of electrons

Where F= Faraday's constant= 96500 C

So, 12F moles of electrons are transferred.

Learn more about Faraday's Law here,

brainly.com/question/27985929

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