If you want to produce 6.2 moles nacl, how many moles of na will you need if you have excess cl2

Chemistry

1 answer:

irinina [24]3 years ago

3 0

Answer:

6.2moles of Na are needed.

Explanation:

First, we need to generate a balanced equation for the reaction between sodium and chlorine to produce sodium chloride. This is illustrated below:

2Na + Cl2 —> 2NaCl

From the equation,

2moles of Na produced 2moles of NaCl.

Therefore Xmol of Na will produce 6.2moles of NaCl i.e

Xmol of NaCl = (2 x 6.2)/2 = 6.2moles

Therefore, 6.2moles of Na are needed to produce 6.2moles of NaCl

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What mass of nitrogen is needed to fill an 855 L tank at STP?

scoundrel [369]

Answer:

It takes 1,068.76 grams of nitrogen to fill an 855 L tank at STP.

Explanation:

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C or 273.15 °K are used and are reference values for gases.

On the other side, the pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

So, in this case:

P= 1 atm
V= 855 L
n= ?
R= 0.082 $\frac{atm*L}{mol*K}$
T= 273.15 K

Replacing:

1 atm* 855 L= n* 0.082 $\frac{atm*L}{mol*K}$ * 273.15 K

Solving:

$n=\frac{1 atm* 855 L}{0.082\frac{atm*L}{mol*K} *273.15 K }$

n= 38.17 moles

Being the molar mass of nitrogen N2 equal to 28 g / mol, you can apply the following rule of three: if there are 28 grams in 1 mole, how much mass is there in 38.17 moles?

$mass=\frac{38.17 moles*28 grams}{1 mole}$