Answer:
The equilibrium will remain at the same conditions because there is no effect and difference in the partial pressure which in turn affect the equilibrium state.
Explanation:
- As Nitrogen is an inert gas therefore it will not react with either the reactants or products.
- Also as the addition is being made by maintaining the volume of flask as constant, thus there will be no difference in the partial pressure of the individual components of the mixture by addition of the Nitrogen gas.
- An increase in pressure is observed but the effect is not aiding or retreating the equilibrium conditions
It will sink because water has a density of 1. and 1.1 is greater than 1 which means that the object is denser than the water so it will cause it to sink
Answer:
Root mean squared velocity is different.
Explanation:
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In this case, since we have a mixture of oxygen and nitrogen at STP, which is defined as a condition whereas T = 298 K and P = 1 atm, we can infer that these gases have the same temperature, pressure, volume and moles but a different root mean squared velocity according to the following formula:
Since they both have a different molar mass (MM), nitrogen (28.02 g/mol) and oxygen (32.02 g/mol), thus we infer that nitrogen would have a higher root mean squared velocity as its molar mass is less than that of oxygen.
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Answer:
0.735M
Explanation:
The balanced equation of reaction is:
HCl + KOH ===> KCl + H2O
Using titration equation of formula
CAVA/CBVB = NA/NB
Where NA is the number of mole of acid = 1 (from the balanced equation of reaction)
NB is the number of mole of base = 1 (from the balanced equation of reaction)
CA is the concentration of acid = 2.5M
CB is the concentration of base = to be calculated
VA is the volume of acid = 14.7mL
VB is the volume of base = 50mL
Substituting
2.5×14.7/CB×50 = 1/1
Therefore CB =2.5×50×1/14.7×1
CB= 0.735M
The two resonating structures of Nitrous Acid are shown below. Lone pair of electrons, single and multiple bonds and non zero formal charges (red color) are also specified.
Among these two structures the structure on the left lacking formal charge is the most stable form. The instability of second resonating structure is due to the fact that it contains two formal charges (the lesser the number of formal charges the greater is the stability). Secondly in this structure one oxygen atom is having +1 formal charge. Oxygen being more electronegative feel hostile towards positive formal charge.