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kati45 [8]
3 years ago
8

What can this simplify to?

Mathematics
1 answer:
Mkey [24]3 years ago
7 0
<u>→ Chapter : Exponentiation ←</u>
<u><em>≡ We know that:</em></u>
⇔ \frac{a^{x}}{a^{y}}=a^{(x-y)}
⇔ \frac{1}{a^{-b}}=a^{b}

<u><em>≡ Solution:</em></u>
⇒ \frac{4^{2}g^{3}p^{-2}}{4^{5}g^{12}m^{-5}}
⇒ [4^{(2-5)}].[g^{(3-12)}].[p^{-2}].[m^{5}]
⇒ [4^{-3}].[g^{-9}].[p^{-2}].[m^{5}]
∴ \boxed{\frac{1}{64}g^{-9}p^{-2}m^{5}} or \boxed{\frac{m^{5}}{64g^{9}p^{2}}}

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