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4 years ago

What can this simplify to?

Mathematics

1 answer:

Mkey [24]4 years ago

7 0

→ Chapter : Exponentiation ←
≡ We know that:
⇔ $\frac{a^{x}}{a^{y}}=a^{(x-y)}$
⇔ $\frac{1}{a^{-b}}=a^{b}$

≡ Solution:
⇒ $\frac{4^{2}g^{3}p^{-2}}{4^{5}g^{12}m^{-5}}$
⇒ $[4^{(2-5)}].[g^{(3-12)}].[p^{-2}].[m^{5}]$
⇒ $[4^{-3}].[g^{-9}].[p^{-2}].[m^{5}]$
∴ $\boxed{\frac{1}{64}g^{-9}p^{-2}m^{5}}$ or $\boxed{\frac{m^{5}}{64g^{9}p^{2}}}$

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(a+b)2= -------/ correct answer please

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Answer:

$a^{2}+2ab+b^{2}$

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3 years ago

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a pizza place charges $15 for a pepperoni pizza and $12 for a cheese pizza. the goal is to sell $540 in pizza for the day. The s

Ede4ka [16]

The pizza place should sell 45 cheese pizza in order to reach daily goal.

Step-by-step explanation:

Let, x=pepperoni pizzas and y= cheese pizzas.

And 15x+12y=540

If pizza place runs out of pepperoni pizza, then x=0 we need to find how many cheese pizza (y) must be sold to achieve the goal.

Putting x=0 and finding y,

$15x+12y=540\\15(0)+12y=540\\12y=540\\y=\frac{540}{12} \\y=45$

So, The pizza place should sell 45 cheese pizza in order to reach daily goal.

Keywords: Word Problems

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3 years ago

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DaniilM [7]

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4 years ago

PLEASE HELP WITH AN EXPLANATION.

Paladinen [302]

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3 years ago

A thermometer is taken from an inside room to the outside, where the air temperature is 20° f. after 1 minute the thermometer re

fomenos

The change in the temperature is proportional to the difference in temperatures. Let's call the initial temperature of the room and the thermometer $E_0$ and the current temperature $E(t)$ where $t$ is the elapsed time in minutes. The outside temperature is 20 F.

Newton's Law of Cooling:

$E(t) - 20 = (E_0 - 20) e^{- k t}$

We're given $E(1)=70 \textrm{ and } E(5)=45$

$70-20 = (E_0 - 20) e^{-k}$

$45-20 =(E_0 - 20) e^{-5k}$

Dividing,

$\dfrac{50}{25}=e^{4k}$

$k = \dfrac 1 4 \ln 2$

Now,

$E(t) - 20 = (E_0 - 20) e^{- k t}$

$E_0 = 20 + (E(t) - 20)e^{k t}$

$E_0 = 20 + (E(1) - 20)e^{k}$

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4 years ago