Question

What can this simplify to?

Answer 1

→ Chapter : Exponentiation ←
≡ We know that:
⇔ $\frac{a^{x}}{a^{y}}=a^{(x-y)}$
⇔ $\frac{1}{a^{-b}}=a^{b}$

≡ Solution:
⇒ $\frac{4^{2}g^{3}p^{-2}}{4^{5}g^{12}m^{-5}}$
⇒ $[4^{(2-5)}].[g^{(3-12)}].[p^{-2}].[m^{5}]$
⇒ $[4^{-3}].[g^{-9}].[p^{-2}].[m^{5}]$
∴ $\boxed{\frac{1}{64}g^{-9}p^{-2}m^{5}}$ or $\boxed{\frac{m^{5}}{64g^{9}p^{2}}}$