An object has more momentum if it has what?

In which structure would you find a nucleus

11111nata11111 [884]

Answer:

cell

Explanation:

cell constist of nucleus and other organelles

3 0

3 years ago

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Determine whether the following statement is true or false: Because introns are largely genetic junk, they do not need to be rem

uysha [10]

Answer:

False

Explanation:

Introns need to be removed precisely because the reading frame will be shifted if removed even single nucleotide too many or leaving an intronic nucleotide in the spliced mRNA .

Extra amino acids will be inserted if large pieces of introns are left in the mature messenger RNA.

In both cases, aberrant protien will be produced if the RNA splicing is not precise, hence they are needed to be removed by precision.

4 0

3 years ago

Researchers want to study behaviors in lions. They

Romashka-Z-Leto [24]

The limitation in the behavior of lions is that the lions living in a group called a pride , in which lions have strong bond and do not accept a stranger.

<h3>What is pride and how lions behave in social lion group?</h3>

A study showed that most of the lions living and sharing same geographical area have friendly behavior.
Pride is a group of lions in which lions interact with each other and share a close bond and do not accept a stranger.
A pride comprises of total thirty lions at max , above which pride is not a group .
Behavior like liking , meowing is amongst the friendly behavior lion shows towards other lion.
The female lions defends the cub , comparatively to the father of the cub.

To know more about lions visit:

brainly.com/question/321742

#SPJ13

6 0

1 year ago

which of these properties, used alone, would be least useful in identifying most minerals? A color B luster C streak D density

Tomtit [17]

Answer:

A-color

Explanation:

Minerals could have the same color, and you can't depend on color to tell you that.

6 0

3 years ago

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2. Dominant trait: cleft chin (C) Mother’s gametes: Cc

andre [41]

.2. Offspring Genotypes will be Cc or cc.

Offspring phenotypes : Cleft chin or no cleft chin.

% chance child will have cleft chin: 50%

3. % chance child will have arched feet: 25%

4. % chance child will have blonde hair: 50%

5. % chance child will have normal vision: 25%

Explanation:

CASE 1 :

Dominant trait: cleft chin (C)

Recessive trait: lacks cleft chin (c)

Father’s gametes: cc

Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents= $\frac{1}{2}C + \frac{1}{2} c$ ........(i)

Gametes of cc parents =<u> </u> $\frac{1}{2}c + \frac{1}{2}c$ .........(ii)

Combining (i) and (ii) we get,

$\frac{1}{2} Cc + \frac{1}{2} cc$

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin = $\frac{0.5}{1}$ ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

A from mother, a from father =Aa

a from mother, A from Father = Aa

a from mother, a from father = aa

Gametes of Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

Gametes of other Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

$\frac{1}{4} AA + \frac{1}{4} Aa$

+ $\frac{1}{4} Aa$ + $\frac{1}{4} aa$

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = $\frac{0.25}{1}$ × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive (bb)

Father’s gametes: Heterozygous (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in half Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous (Ff)

Father’s gametes: Heterozygous (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF then phenotype farsightedness

Genotype Ff then phenotype farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

3 0

3 years ago