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frosja888 [35]
3 years ago
10

The sum of two numbers is 73. When the smaller number is subtracted from twice the greater number, the result is 50. Find the nu

mbers. Please use a let statment and an algebraic solution. Thanks! :)
Mathematics
1 answer:
Karolina [17]3 years ago
5 0

Answer:

The big number is 41 and the small number is 32.

Step-by-step explanation:

b + s = 73

2b - s = 50        Add these equations together

3b = 123            Divide both sides by 3

b = 41

Now plug this into the first equation to find s

41 + s = 73

-41       - 41

s = 32

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