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iogann1982 [59]

3 years ago

12

The ____________ theorem states the binomial x – r is a factor if and only if the remainder equals zero.

1 answer:

Oxana [17]3 years ago

8 0

<span>The Remainder theorem states the binomial x – r is a factor if and only if the remainder equals zero.</span>

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Can someone solve this for me with their explanation please?

Lana71 [14]

First you want to subtract 36

so it looks like this $\sqrt[4] {(4x+164)^3}=64$

Then you want to cancel out the square root 4 by raising that to the 4th power (you must do this to both sides)

${(4x+164)^3}=64^4$ which is equal to ${(4x+164)^3}=16777216$

Then you take the cube root to both sides [tex]\sqrt[3]{(4x+164)^3}=\sqrt[3]{16777216}[tex]

Then you end up with the equation 4x+164=256

Then subtract 164 to both sides

4x=92

then divide 92 by 4

Then you get x=23

7 0

4 years ago

Select ALL the correct answers.

aksik [14]

Answer: I think it’s A the cylinder

Step-by-step explanation:

8 0

3 years ago

Which equations listed below contain like terms?

Marianna [84]

Answer:

B

Step-by-step explanation:

14p and 3p have the same variable

6 0

3 years ago

What is the property of -8+3 = 3+ (-8)

Marizza181 [45]

Answer:

12

Step-by-step explanation:

its not 12 im just trying to make an account

7 0

3 years ago

Guyss please help me with this question. I tried a thousand times but it's still incorrect.

Shalnov [3]

Answer: $17.68cm$

Step-by-step explanation:

Using the area formula of a cone, find the height first.

$A=\pi r(r+\sqrt{h^2+r^2})$

Solve for h,

Begin by dividing by $\pi r$

$\frac{A}{\pi r}=r+\sqrt{h^2+r^2}$

Subtract r.

$\frac{A}{\pi r}-r=\sqrt{h^2+r^2}$

Square both sides.

$(\frac{A}{\pi r}-r)^2=(\sqrt{h^2+r^2})^2$

$(\frac{A}{\pi r}-r)^2=h^2+r^2$

Subtract $r^2$

$(\frac{A}{\pi r}-r)^2-r^2=h^2$

Extract the square root.

$\sqrt{(\frac{A}{\pi r}-r)^2-r^2 } =\sqrt{h^2}$

$\sqrt{(\frac{A}{\pi r}-r)^2-r^2 } =h$

Plug in your values.

$\sqrt{[\frac{670cm^2}{(3.14)(8cm)}-(8cm)]^2-(8cm)^2 } =h$

Solve;

$\sqrt{[\frac{670cm^2}{25.12cm}-(8cm)]^2-(8cm)^2 } =h$

$\sqrt{[26.67cm-(8cm)]^2-(8cm)^2 } =h$

$\sqrt{(18.67cm)^2-(8cm)^2 } =h$

$\sqrt{348.57cm^2-64cm^2}=h$

$\sqrt{284.57cm^2}=h$

$15.77cm=h$

------------------------------------------------------------------

Now, to find the slant height use this formula: $l=\sqrt{h^2+r^2}$

$l=\sqrt{(15.77cm)^2+(8cm)^2}\\l=\sqrt{248.69cm^2+64cm^2}\\ l=\sqrt{312.69cm^2}\\ l=17.68cm$

8 0

3 years ago