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Ludmilka [50]
3 years ago
15

A plane averaged 800 mph on a trip going​ east, but only 400 mph on the return trip. The total flying time in both directions wa

s 4.5 hr. What was the​ one-way distance?
Mathematics
1 answer:
galina1969 [7]3 years ago
5 0

Answer:

1200 miles.

Step-by-step explanation:

Let d represent one way distance.

We have been given that a plane averaged 800 mph on a trip going​ east, but only 400 mph on the return trip.

\text{Time}=\frac{\text{Distance}}{\text{Speed}}

The time taken while going east would be \frac{d}{800}.

The time taken while returning back would be \frac{d}{400}.

Since the total flying time in both directions was 4.5 hr, so we will equate sum of both times with 4.5 as:

\frac{d}{800}+\frac{d}{400}=4.5

Make a common denominator:

\frac{d}{800}+\frac{d*2}{400*2}=4.5

\frac{d}{800}+\frac{2d}{800}=4.5

\frac{d+2d}{800}=4.5

\frac{3d}{800}=4.5

\frac{3d}{800}\times \frac{800}{3}=4.5\times \frac{800}{3}

d=1.5\times \frac{800}{1}

d=1200

Therefore, the one-way distance was 1200 miles.

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