Since the required number is between 234 and 250, then the first digit of the number is 2 and the second digit can either be 3 or 4.
Let the second and the third digits be x and y respectively, then
2 + x + y = 2y
Consider when the second digit is 3, then
2 + 3 + y = 2y
5 = y
Thus, the number is 235.
Similarly, consider when the second digit is 4, then
2 + 4 + y = 2y
6 = y
Thus, the number is 246.
Since the required number is an even number, therefore, Isabel's number is 246.
Okay, first thing is you want to have x and y all alone. So you need to solve the equations.
Equation 1:
5x+4y=12 (you want to subtract 5x on both sides to get y on one side and x on the other)
5x+4y=12
<u>-5x -5x
</u><u> 4y=12-5x</u> (Now if you want x and y alone you want to divide 4 on both sides)
4
y=3-1.25x Now that's you equation
Equation 2: (Basically the same steps for the 1st equation)
3x-3y=18 (Subtract 3x on both sides)
<u>-3x -3x </u><u>
</u><u>-3y=18-3x </u> (Now you divided by -3 on both sides)
-3
y=-6+x (you might notice why is there only 1 x, well because -3 divided by -3 is going to be a positive 1. You can either put a "x" or a 1x, doesn't really matter).
now since you have the two equations simplified you want to solve by doing multi-step.
3-1.25x=-6+x (Now you want to add 1.25x so you can get rid of the negative x)
<u> +1.25x +1.25x
</u> 3= -6+2.25 (Remember x alone is like 1, so it's like 1+1.25, next you want to add 6 on both sides. So you have a number and a variable all alone).
3=-6+2.25x
<u>+6 +6
</u><u>9 </u><u>= </u><u>2.25x</u> (Next you divided 2.25 on both sides)
2.25 2.25
Answer:
x =4
If your not sure, you can plug in or replace x with 4. :D
<em>I really do hope this help you understand :D </em>
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1. The first 10 multiples of 13 are 13, 26, 39, 52, 65, 78, 91, 104, 117, and 130.
2. x - 5
3. x + 80
Heyy I'm not sure if I'm right
12x^4 + 2x^3 - 30x^2
to find the GCF, let's first look at the coefficients.....the GCF of 12,2,and 30 is 2.
as for the variables....pick the one with the smallest exponent...and that would be x^2
so the GCF of this polynomial is 2x^2 <=