What is the vertex of the quadratic function f(x) = (x - 3)(x

Paha777 [63]

Blaise Pascal (June 19, 1623 - August 19, 1662) was a great contributor to math, science, and philosophy, especially Christian philosophy. Interesting Blaise Pascal Facts: Pascal's early education in France was conducted at home by his father due to the prodigious talent and understanding he showed as a child. Did u mean pascal instead of pasical becaus ethere is no such thing. Hope I helped :)

4 0

2 years ago

What is the simplified form of the following expression?

kogti [31]

Answer:

$\sqrt{3}$

Step-by-step explanation:

We will be using 2 properties of radicals in this simplification (outlined below).

$\sqrt{a*b}=\sqrt{a}* \sqrt{b}$
$\sqrt{a}*\sqrt{a}=a$

Let's simplify this:

$2\sqrt{27} +\sqrt{12} -3\sqrt{3}-2\sqrt{12}\\ =2\sqrt{9*3}+\sqrt{4*3} -3\sqrt{3}-2\sqrt{4*3} \\=2\sqrt{9} \sqrt{3} +\sqrt{4} \sqrt{3}-3\sqrt{3}-2\sqrt{4} \sqrt{3} \\=2(3)\sqrt{3}+(2)\sqrt{3} -3\sqrt{3}-2(2)\sqrt{3} \\ =6\sqrt{3} +2\sqrt{3}-3\sqrt{3}-4\sqrt{3} \\=\sqrt{3}$

First answer choice is right.

5 0

3 years ago

I need help on this question

pogonyaev

Answer:

315

Step-by-step explanation:

1. This is not a scale rectangle and it angers me.

2. All you have to do is draw proportions.

5x7=35

15x21=315

Youll notice that 5x3=15 and 7x3=21 so it’s just proportions!

5 0

3 years ago

HELPPP FOR BRIANLEST???!

dedylja [7]

Answer:

3/17

Step-by-step explanation:

multicolored and 1 passenger (3) over total (17)

3/17 doesn't simplify

4 0

1 year ago

Find the derivative of

kirill [66]

Answer:

$\displaystyle y'(1, \frac{3}{2}) = -3$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

$\displaystyle y = \frac{3}{2x^2}$

$\displaystyle \text{Point} \ (1, \frac{3}{2})$

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y = \frac{3}{2}x^{-2}$
Basic Power Rule: $\displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}$
Simplify: $\displaystyle y' = -3x^{-3}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{-3}{x^3}$

Step 3: Solve

Substitute in coordinate [Derivative]: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1^3}$
Evaluate exponents: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1}$
Divide: $\displaystyle y'(1, \frac{3}{2}) = -3$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

6 0

2 years ago

What is the vertex of the quadratic function f(x) = (x - 3)(x - 2)?