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4 years ago

Calculate the heat absorbed by

Physics

1 answer:

IrinaK [193]4 years ago

6 0

Answer:

Heat required to heat the given amount of water is

$Q = 3.47 \times 10^7 J$

Explanation:

As we know that heat required to raise the temperature of water is given as

$Q = ms\Delta T$

here we have

m = 105 kg

s = 4180 J/kg C

now we have

$\Delta T = 99 - 20$

now we have

$Q = 105 (4180)(99 - 20)$

$Q = 3.47 \times 10^7 J$

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Which of the following is a true statement about mass and weight? a. Mass is a measure of how much matter an object has, while w

natka813 [3]

Answer:

b option mass will not change based on location while weight will changr based on gravitational pull

bcz in the formula of weight w=mg

so w is directly proportional to g

8 0

4 years ago

The freezer compartment in a conventional refrigerator can be modeled as a rectangular cavity 0.3 m high and 0.25 m wide with a

Anon25 [30]

Answer:

Thickness of Styrofoam insulation is 0.02741 m.

Explanation:

Given that,

Height = 0.25 m

Depth = 0.5 m

Power = 400 W

Temperature = 33°C

We need to calculate the area of Styrofoam

Using formula of area

$A=2(lb+bh+hl)$

Put the value into the formula

$A=2(0.3\times0.5+0.25\times0.5+0.5\times0.3)$

$A=0.85\ m^2$

Inner surface temperature of freezer

$T_{i}=-10°C=263\ K$

Outer surface temperature of freezer

$T_{o}=33+273=306\ K$

We need to calculate the thickness of Styrofoam insulation

Using Fourier law,

$q=\dfrac{kA}{L}(T_{o}-T_{i})$

$L=\dfrac{kA}{q}(T_{o}-T_{i})$

Put the value into the formula

$L=\dfrac{0.30\times0.85}{400}(306-263)$

$L=0.02741\ m$

Hence, Thickness of Styrofoam insulation is 0.02741 m.

8 0

3 years ago

A gymnast does a one-arm handstand. The humerus, which is the upper arm bone between the elbow and the shoulder joint, may be ap

igor_vitrenko [27]

Answer:

$= 5.241 \times 10^{-5} m$

Explanation:

Given:

Length of cylinder is, L = 0.27 m

Outer radius of cylinder is, r_out = 1.12×10^{-2} m

Inner radius of cylinder is, r_in = 3.9×10^{-3} m

Mass of person, m = 60 kg

Young's modulus , Y = 9.4×10^9 N/m2

(a)

Compressional strain of humerous is,

$Strain = \frac{Stress}{Young's\ modulus}$

$\frac{\Delta L}{L_0} = \frac{\frac{F}{A}}{Y}$

$= \frac{(mg)}{\pi(r_out^2 - r_in^2 )Y}$

$= \frac{(60 kg)(9.8 m/s2 )}{(\pi)[( 1.12\times 10^{-2})^2 - (3.9\times 10^{-3} m)^2] (9.4\times 10^9 N/m2 )}[tex] [tex]= 1.80\times 10^{-4} m$

(b) Let assume that humerous is compressed by ΔL

Since, strain = ΔL/L0

$(1.80 \times 10^{-4} m) = ΔL / 0.29 m$

Thus,

$ΔL = (4.56 \times 10^{-4} m)(0.29 m)$

$= 5.241 \times 10^{-5} m$

7 0

3 years ago

How does the nuclear charge relate to the energy of the 1s orbital?

nlexa [21]

Explanation:

Effective nuclear charge is defined as he net positive charge experienced by an electron in an atom. It is termed "effective" because the shielding effect of electrons prevents higher orbital electrons from experiencing the full nuclear charge of the nucleus due to the repelling effect of inner-layer electrons.

The 1s is the closest shell to the nucleus of an therefore maximum nuclear charge is experienced. The formula for effective nuclear charge is:

Zeff = Z – S

where

Z = the number of protons in the nucleus, and

S = the shielding constant, the average number of electrons between the nucleus and the electron.

Hence, the energy required to remove an electron from the 1s orbital is the strongest.

3 0

4 years ago

A branch of mechanics dealing with the mathematical methods of describing motion

alexdok [17]

Kinematics is the branch of Physics that deals with
the mathematical methods of describing motion.

3 0

4 years ago