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Elenna [48]
4 years ago
8

explain why a high speed collision between two cars would cause more damage than a low speed collision between the same two cars

?
Physics
1 answer:
Sonja [21]4 years ago
6 0
I've would cause more damage, because there is nore momentum and input force equals output force and the momentum is transferred between the two cars more so than if they had a lower velocity
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Newton's second law of motion can also be described as...
Irina-Kira [14]

Answer


B. F=ma



Explanation

The Newton's laws of motion tries to explain the how bodies behave and the energy changes when theys are in motion. For the 3 of them to hold, the bodies must be moving in a straight line and with constant velocity.

The second one states that, "the change of momentum of a moving body is directly proportional to the force producing it and it takes place to the direction of force."

From the choices given, the appropriate answer is B. F=ma

6 0
3 years ago
On a sunny day, does a bird or an aeroplane flying high in the sky cast its
Ilia_Sergeevich [38]

Answer:

Hope it helps

Explanation:

The higher the bird flies, the bigger the shadow it casts, however, for the shadow to be visible enough the plane or bird would have to be close to the line directly from the sun.

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3 years ago
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LARGER vibration produces a higher ............
balandron [24]
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8 0
4 years ago
Please help Math Phys
Lorico [155]

Answer:

269 m

45 m/s

-58.6 m/s

Explanation:

Part 1

First, find the time it takes for the package to land.  Take the upward direction to be positive.

Given (in the y direction):

Δy = -175 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(-175 m) = (0 m/s) t + ½ (-9.8 m/s²) t²

t = 5.98 s

Next, find the horizontal distance traveled in that time:

Given (in the x direction):

v₀ = 45 m/s

a = 0 m/s²

t = 5.98 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (45 m/s) (5.98 s) + ½ (0 m/s²) (5.98 s)²

Δx = 269 m

Part 2

Given (in the x direction):

v₀ = 45 m/s

a = 0 m/s²

t = 5.98 s

Find: v

v = at + v₀

v = (0 m/s²) (5.98 s) + (45 m/s

v = 45 m/s

Part 3

Given (in the y direction):

Δy = -175 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: v

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (-9.8 m/s²) (-175 m)

v = -58.6 m/s

6 0
3 years ago
What is the pressure 100m below the surface of the sea , if the density of sea water is 1150kg/m3
Olin [163]
The pressure at 100 meters below the surface of sea water with a density of 1150kg is 145.96 psi.
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