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Alex
3 years ago
6

Which of the following formulas is used to calculate the probability of independent events A and B?

Mathematics
1 answer:
lapo4ka [179]3 years ago
3 0
D. P(A and B) = P(A) P(B)
You might be interested in
I need help in mathematics
lapo4ka [179]

Answer:

B. 75.36 cubic cm

Step-by-step explanation:

We will use the formula V=π times r² times h

so, V= 3.14 times 2² times 6

so, V= 3.14 times 4 times 6

= 3.14 times 24

=75.36 cubic cm

<h2><em>Please mark me as brainliest</em></h2>
6 0
3 years ago
What is parallel to 2x-y=1 and contains (4, -6)? Please show your work!
Contact [7]

k:\ y=m_1x+b_1\\\\l:\ y=m_2x+b_2\\\\l\ ||\ k\iff m_1=m_2\\\\\text{We have}\\\\k:\ 2x-y=1\ \ \ |-2x\\-y=-2x+1\ \ \ \ |\cdot(-1)\\y=2x-1\to m_1=2\\\\l:\ y=m_2x+b\\\\l\ ||\ k\iff m_2=2\\\\l:\ y=2x+b\\\\\text{The line l contains (4, -6)}\\\\\text{Put the values of coordinates to the equation of line l}\\\\-6=2(4)+b\\-6=8+b\ \ \ \ \ |-8\\b=-14\\\\Answer:\ y=2x-14\to 2x-y=14

5 0
3 years ago
Find the values of x and y
zhuklara [117]

You can use a tangent:

tangent=\dfrac{opposite}{adjacent}

We have opposite = 17 and adjacent = x.

\tan30^o=\dfrac{\sqrt3}{3}

substitute:

\dfrac{17}{x}=\dfrac{\sqrt3}{3}       cross multiply

x\sqrt3=(3)(17)     multiply both sides by √3

x(\sqrt3)(\sqrt3)=51\sqrt3

3x=51\sqrt3      divide both sides by 3

x=17\sqrt3

Use the Pythagorean theorem:

y^2=(17\sqrt3)^2+17^2\\\\y^2=289(\sqrt3)^2+289\\\\y^2=289\cdot3+289\\\\y^2=867+289\\\\y^2=1156\to y=\sqrt{1156}\\\\y=34

-------------------------------------------------------------------------------------------------

Other method.

30^o-60^o-90^o triangle.

The sides are in the ratio 1:2:\sqrt3\to17:y:x

Therefore

17:(2\cdot17):(17\sqrt3)\to17:34:17\sqrt3\to x=34,\ y=17\sqrt3

 


4 0
3 years ago
A spinner is divided into four equal sections labeled A, B, C, D. After 50 trials, the spinner landed on A 14 times, on B 13 tim
svp [43]

Answer:

17/25

Step-by-step explanation:

P(not red)=Number of Skittles Not Red/Total Number of Skittles

6 0
2 years ago
QUICKKKKKKKK
zavuch27 [327]
See attached picture of graph

6 0
3 years ago
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