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aliya0001 [1]
3 years ago
10

2C4H10 + 13O2 --> 8CO2 + 10H2O

Chemistry
2 answers:
Makovka662 [10]3 years ago
7 0
The answer is C: the reaction is a single replacement!
olga2289 [7]3 years ago
5 0

Answer:

c

Explanation:

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I have a buddy who recycles electronics, and isolates metals from the connector pins electrical boards. He isolates gold, for ex
bogdanovich [222]

Solution :

In the process to isolate gold that has a 80 percent yield, a 3.00 g of Au is being isolated.

That is, the actual yield of Au is 3. 00 g

Therefore, we need to find the theoretical yield.

As we know,

$\text{percent yield}=\frac{\text{actual yield}}{\text{theoretical yield}} \times 100$

$\text{theoretical yield}=\frac{\text{actual yield}}{\text{present yield}} \times 100$

As actual yield = 3.00 g

    percent yield = 80 %

So, theoretical yield = $\frac{3.00}{80} \times 100$

                                  = 3.75 g

Thus he should be able to get 3.75 g which is the theoretical yield of Au.

5 0
3 years ago
Which is an example of an atom?
xenn [34]
It is A)The smallest unit of Ne 

5 0
4 years ago
“Sugar will dissolve faster in cold water than in hot water.” Is this statement true or false? EXPLAIN using evidence from past
Mice21 [21]

Answer:

false

Explanation:

6 0
3 years ago
Read 2 more answers
In one of his experiments, Lavoisier placed 10.0 grams of mercury (II) oxide into a sealed container and heated it. The mercury
inysia [295]

Oxygen gas produced : 0.7 g

<h3>Further explanation</h3>

Given

10.0 grams HgO

9.3 grams Hg

Required

Oxygen gas produced

Solution

Reaction⇒Decomposition

2HgO(s)⇒2Hg(l)+O₂(g)

Conservation of mass applies to a closed system, where the masses before and after the reaction are the same

mass of reactants = mass of products

mass  HgO = mass Hg + mass O₂

10 g = 9.3 g + mass O₂

mass O₂ = 0.7 g

4 0
3 years ago
HELP ASAP!!
Ksju [112]
109/8.56=12.7
50+12.7
V=62.7

Mass= Volume x Density so i divided the mass and density to get the volume. and afterwards i would just add it to the mass to get my final answer

4 0
3 years ago
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