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den301095 [7]
3 years ago
12

The energy released during a nuclear reaction in a power plant is directly used to __________

Chemistry
1 answer:
Paha777 [63]3 years ago
4 0
C is the answer........
You might be interested in
Distinguish between zinc nitrate and lead nitrate ​
Kobotan [32]

Answer:

Zinc nitrate gives white ppt. which dissolves in excess ammonium hydroxide and produce a colorless solution whereas lead nitrate gives a chalky white ppt. of lead hydroxide which doesnot dissolve.

Explanation:

Hope this helps :)

7 0
3 years ago
Sheena has a lump of sodium, a lump of potassium and a lump of lithium, but they’ve got mixed up and she doesn’t know which one
Arada [10]

Answer:

Explanation:

Just saw your request regarding answering this so here it is:

All of them belong of Group 1 in periodic table and thus are highly reactive! Pattern of reactivity for Group 1 (Alkali metals) increases as you move down the group as their radius keeps increasing and thus electrons can be easily lost. Thus, to ID the lumps, Sheena should look at their reactivity and she should get the following trend:

Most reactive: Potassium (K)

Intermediate: Sodium (Na)

Least reactive: Lithium (Li)

Hope it helps!

5 0
3 years ago
Octane has a density of 0.692 g/ml at 20∘c. how many grams of o2 are required to burn 17.0 gal of c8h18
german

156251.099 grams of O₂ are required to burn 17.0 gal of C₈H₁₈

<h3>Further explanation</h3>

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of mass

The unit of density can be expressed in g / cm³ or kg / m³

Density formula:

\large{\boxed{\bold{\rho~=~\frac{m}{V} }}}

ρ = density

m = mass

v = volume

1 gal equal to = 3785.41 ml

then 17.0 gal = 17 x 3785.41 = 64351.97 ml Octane

grams Octane = ρ x ml

grams Octane = 0.692 g.ml x 64351.97

grams Octane = 44531.563

molar mass Octane (C₈H₁₈) = 114

mole Octane = grams : molar mass

mole Octane = 44531.563  : 114

mole Octane = 390.627

From the reaction

C₈H₁₈ + 25/2 O₂ ⇒ 8 CO₂ + 9H₂O

mole C₈H₁₈ : mole O₂ = 1 : 25/2

mole\:O_2\:=\:\frac{25}{2} \times\:390.627

mole O₂ = 4882.846

grams O₂ = mole x molar mass

grams O₂ = 4882.846 x 32

grams O₂ = 156251.099

<h3>Learn more </h3>

moles of water

brainly.com/question/1405182

grams of oxygen required

brainly.com/question/8175791

mass of copper required

brainly.com/question/1680090

Keywords: Octane,  mole, mass, gal, density

5 0
3 years ago
A rock sample from the moon includes a mineral that contains small amounts of the radioactive isotope Potassium-40 and its daugh
Simora [160]

Answer:

There were originally 8 atoms of Potassium-40.

Explanation:

The half-life of a radioactive material is the time taken for half the original material to decay or the time required for a quantity of the radioactive substance to reduce to half of its initial value.

If the original material formed without any Argon-40, it means that the atoms originally present were Potassium-40 atoms.

Presently, there are 7 Argon-40 atoms for every 1 of Potassium-40, we can deduce the number of half-lifes the Potassium-40 has undergone as follows :

After one half-life, (1/2) there will be one Potassium-40 atom for every Argon-40 atom.

After a second half life, 1/2 × 1/2 = 1/4: there will be one Potassium-40 atom for every three atoms of Argon-40.

After a third half-life, 1/4 × 1/2 = 1/8: there will be one Potassium-40 atom for every 7 atoms of Argon-40.

Since there are 1/8 atoms of Potassium-40 presently, there were originally 8 atoms of Potassium-40.

6 0
3 years ago
14. Calculate the mass in grams of oxygen required to react completly with 0.75 moles of Aluminum.
cluponka [151]
  • 3mols of O_2 react with 4mol of Al
  • 3/4=0.75mol O_2 react with 1mol of Al

Moles of O_2:-

  • 0.75(0.75)
  • 0.5625mol

Mass of O_2:-

  • moles(Molar mass)
  • 0.5625(32)
  • 18g

Option B

8 0
2 years ago
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