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Tasya [4]
4 years ago
6

Which is a derived unit? a.) kilogram b.) joule c.) micrometer d.) millimeter

Physics
2 answers:
DaniilM [7]4 years ago
6 0

Answer : The correct option is, (b) joule

Explanation :

Derived unit : Derived units are derived from some basic units.

From the given options, option a, c and d are the basics units. While the option b is the derived unit.

The derived unit Joule is the unit of work which is derived as,

work=force\times displacement

The unit of force is newton (N) and 1 N is equal to the 1\text{ Kg }m/s^2

The unit of displacement is meter (m).

Now by putting these units in above formula, we get the unit of work.

work=(1\text{ Kg }m/s^2)\times (m)=1\text{ Kg }m^2/s^2=Joule

Hence, the derived unit is, joule.

Dovator [93]4 years ago
5 0
Joule us a derived unit
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3 years ago
With what minimum speed must you toss a 130 gg ball straight up to just touch the 15-mm-high roof of the gymnasium if you releas
xxTIMURxx [149]

Answer:

The initial velocity is 0.5114 m/s or 511.4 mm/s

Explanation:

Let the initial velocity be 'v'.

Given:

Mass of the ball (m) = 130 g = 0.130 kg   [ 1 g = 0.001 kg]

Initial height of the ball (h₁) = 1.4 mm = 0.0014 m   [ 1 mm = 0.001 m]

Final height of the ball (h₂) = 15 mm = 0.015 m

Now, from conservation of energy principle, energy can neither be created nor be destroyed but converted from one form to another.

Here, the kinetic energy of the ball is converted to gravitational potential energy of the ball after reaching the final height.

Change in kinetic energy is given as:

\Delta KE=\frac{1}{2}m(v_f^2-v_i^2)\\Where\ v_f\to Final\ velocity\\v_i\to Initial\ velocity

As it just touches the 15 mm high roof, the final velocity will be zero. So,

v_f=0\ m/s.

Now, the change in kinetic energy is equal to:

\Delta KE = \frac{1}{2}\times 0.130\times v^2\\\\\Delta KE = 0.065v^2

Change in gravitational potential energy = Final PE - Initial PE

So,

\Delta U=mg(h_f-h_i)\\\\\Delta U=0.130\times 9.8\times (0.015-0.0014)\\\\\Delta U=0.017\ J                    [ g = 9.8 m/s²]

Now, Change in KE = Change in PE

0.065v^2=0.017\\\\v=\sqrt{\frac{0.017}{0.065}}\\\\v=0.5114\ m/s\\\\1\ m=1000\ mm\\\\So,0.5114\ m=511.4\ mm\\\\\therefore v=511.4\ mm/s

Therefore, the initial velocity is 0.5114 m/s or 511.4 mm/s

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If the magnitude of F1 is greater than the magnitude of F2, then the box is
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