Crushing increases the ice's surface area. Additionally, cooling from ice happens as a result of convection, which is proportional to area. Thus, breaking up the ice expedites the cooling process.
<h3>What is cooling process?</h3>
When precise and consistent temperature control inside a process is necessary, this sort of cooling is used. Because they can offer cooling capacity independent of variations in the ambient temperature, heat load, and flow needs of the application, chillers are frequently employed to remove heat from a process.
It's important to properly regulate the heat load in many industrial operations. Different components of the whole application might need to be cooled.
Major locations for cooling include:
Direct product cooling
During the molding process, plastic
milling metal products
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Answer:
A. Speed is a scalar quantity and velocity is a vector quantity.
Explanation:
A scalar quantity is one that consists of only a numerical value.
Speed is a scalar quantity because only the instantaneous value is indicated, for example the speedometer of a car that tells you your speed at the moment but not where you are going or in what direction are you going.
On the other hand, velocity is a vector quantity. Because it is composed of a <u>magnitude and a direction</u>, for example 10m/s to the south is a velocity, and 10m/s is a speed.
pH is the measure of the concentration of hydrogen ions in a solution
Answer:
Explanation:
Given that,
5J work is done by stretching a spring
e = 19cm = 0.19m
Assuming the spring is ideal, then we can apply Hooke's law
F = kx
To calculate k, we can apply the Workdone by a spring formula
W=∫F.dx
Since F=kx
W = ∫kx dx from x = 0 to x = 0.19
W = ½kx² from x = 0 to x = 0.19
W = ½k (0.19²-0²)
5 = ½k(0.0361-0)
5×2 = 0.0361k
Then, k = 10/0.0361
k = 277.008 N/m
The spring constant is 277.008N/m
Then, applying Hooke's law to find the applied force
F = kx
F = 277.008 × 0.19
F = 52.63 N
The applied force is 52.63N
The tension in the upper rope is determined as 50.53 N.
<h3>Tension in the upper rope</h3>
The tension in the upper rope is calculated as follows;
T(u) = T(d)+ mg
where;
- T(u) is tension in upper rope
- T(d) is tension in lower rope
T(u) = 12.8 N + 3.85(9.8)
T(u) = 50.53 N
Thus, the tension in the upper rope is determined as 50.53 N.
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