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abruzzese [7]
2 years ago
7

If a small asteroid named ‘B612’ has a radius of only 20 m and mass of

Physics
1 answer:
Molodets [167]2 years ago
4 0

Acceleration produced in the motion of a body under the effect of gravity is called acceleration due to gravity.

It is a vector quantity and it's SI unit is m/s².

It is usually denoted by the symbol g.

Formula of Acceleration due to Gravity:

\boxed{ \bf{g = \dfrac{GM}{r^2}}}

G → Universal Gravitational Constant \sf (6.67 \times 10^{-11} \ Nm^2/kg^2)

M → Mass of the Asteroid (1 × 10⁴ kg)

R → Radius of the Asteroid (20 m)

By substituting values in the equation, we get:

\rm \longrightarrow g = \dfrac{6.67 \times  {10}^{ - 11}  \times 1 \times  {10}^{4} }{20^2} \\  \\  \rm \longrightarrow g  = \dfrac{6.67 \times  {10}^{ - 11 + 4} }{400} \\  \\  \rm \longrightarrow g = 0.016675 \times  {10}^{ - 7}   \\  \\ \rm \longrightarrow g = 1.6675 \times  {10}^{ -9}  \: m {s}^{ - 1}

\therefore Acceleration due to gravity on the surface of small asteroid named ‘B612’ = \sf 1.6675 \times 10^{-9} \ m/s

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Guys No one's answering my question so sad! Once again I'm asking the same question –Here
nexus9112 [7]

For the front glass of the car to get wet, V_c \geq 10 \ m/s.

The given parameters:

  • <em>Speed of the car, = Vc</em>
  • <em>Speed of the rain, = 10 m/s</em>

The relative velocity of the car with respect to the falling rain is calculated as;

V_{C/R} = V_C- V_R

  • If the speed of the car equals the speed of the rain, the rain will fall behind the car.
  • If the speed of the rain is greater than speed of the car, the rain will fall far in front of the car.
  • If the speed of the car is greater than speed of the rain, the rain will fall on the car.

Thus, for the front glass of the car to get wet, V_c \geq 10 \ m/s.

Learn more about relative velocity here: brainly.com/question/17228388

8 0
2 years ago
Imagine a 15kg block moving with a speed of 20m/s. Calculate the kinetic energy of this block. (Show the equation, show your wor
dmitriy555 [2]

Answer:

The answer to your question is:        Ke = 3000 Joules

Explanation:

Data

mass = 15 kg

speed = 20 m/s

Kinetic energy = ?

Equation

               Ke = \frac{1}{2}mv^{2}

               Ke = \frac{1}{2}(15)(20)^{2}

                Ke = 3000 Joules

5 0
3 years ago
Read 2 more answers
Which is an example of a covalent bond? There are fewer than 16 valence electrons in 2 chlorine atoms, but they form a stable bo
Goryan [66]
Covalent bonding is a type of chemical bonding wherein there is a sharing of electrons to achieve chemical stability or the octet rule. For instance, the chlorine atom with one unpaired electron shares an electron to sodium to become stable. In the given examples, the situation that portrays covalent bonding is when Chlorine accepts 1 electron from calcium to form a stable bond.
7 0
2 years ago
A 1.5-kg mass attached to an ideal massless spring with a spring constant of 20.0 N/m oscillates on a horizontal, frictionless t
Molodets [167]

Answer:

Explanation:

a ) angular frequency ω = \sqrt{\frac{k}{m} }

k is spring constant and m is mass attached

ω = \sqrt{\frac{20}{1.5} }

= 3.6515 rad / s

frequency of oscillation n = 3.6515 / (2 x 3.14)

= .5814 s⁻¹

x = .1 mcos(ωt)

= .1 mcos(3.6515t)

b ) maximum speed = ωA , A is amplitude

= 3.6515 x .1

= .36515 m /s

36.515 cm /s

maximum acceleration = ω²A

= 3.6515² x .1

= 1.333 m / s²

c ) Kinetic energy at displacement x

= 1/2 m ω²( A²-x²)

potential energy =1/2 m ω²x²

so 1/2 m ω²( A²-x²) = 1/2 m ω²x²

A²-x² = x²

2x² = A²

x = A / √2

6 0
3 years ago
If element x has 10 electrons, how many of them will be in the second energy level?​
Sati [7]

the second level will have 8 electrons.

6 0
3 years ago
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