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3 years ago

11

A book is sitting in a table. Jackie is pushing the book with a force of 9 N. If the force of friction is 4 N to the left, what

is the net force

1 answer:

Bumek [7]3 years ago

4 0

Answer:

The net force is 5N

Explanation:

A shown in the diagram,

we let P be the force Jackie applied and

$F_r$

be the frictional force.

To get the net force, we subtract the frictional force from the applied force.

This implies that,

$F_n= P-F_r$

$F_n= 9 - 4$

$F_n=5N$

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3 years ago

1 A 75-g ball is projected from a height of 1.6 m with a horizontal velocity of 2 m/s and bounces from a 400-g smooth plate supp

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Answer with explanation:

We are given that

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1 kg=1000 g

Height, $h_1=1.6 m$

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Horizontal velocity, $v_x=2 m/s$

Mass of plate $m_2=400 g=\frac{400}{1000}=0.4 kg$

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Velocity before impact= $u_1=\sqrt{2gh_1}=\sqrt{2\times 9.8\times 1.6}=5.6m/s$

Where $g=9.8 m/s^2$

Velocity after impact, $v_1=\sqrt{2gh_2}=\sqrt{2\times 9.8\times 0.6}=3.4m/s$

According to law of conservation of momentum

$m_1u_1+m_2u_1=-m_1v_1+m_2v_2$

Substitute the values

$0.075\times 5.6+0=-0.075\times 3.4+0.4v_2$

$0.4v_2=0.075\times 5.6+0.075\times 3.4$

$v_2=\frac{0.075\times 5.6+0.075\times 3.4}{0.4}=1.69 m/s$

Velocity of plate=1.69 m/s

b.Initial energy= $\frac{1}{2}m_1v^2_x+m_1gh_1=\frac{1}{2}(0.075)(2^2)+0.075\times 9.8\times 1.6=1.326 J$

Final energy= $\frac{1}{2}m_1v^2_x+m_1gh_2+\frac{1}{2}m_2v^2_2$

Final energy= $\frac{1}{2}(0.075)(2^2)+0.075\times 9.8\times 0.6+\frac{1}{2}(0.4)(1.69)^2=1.162 J$

Energy lost due to compact=Initial energy-final energy=1.326-1.162=0.164 J

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Answer:

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2 years ago

An aircraft maintenance technician walks past a tall hangar door that acts like a single slit for sound entering the hangar. Out

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Answer:

The first minimum would be observed at 41.57°

Explanation:

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λ = wavelength incident on the single slit

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