Answer:
The center of the circle is (2/3, 0) and radius is ±6units
Step-by-step explanation:
Given the equation of a circle given as shown;
(x-2/3)²+y² = 36
To get the radius and centre of the circle, we will compare the equation with the general equation of a circle given as;
(x-a)²+(y-b)² = r² where (a, b) is the centre of the circle and r is the radius.
Comparing with the given equation,
we will see that;
a = 2/3, b = 0 and r² = 36
If r² = 36
r = ±√36
r = ±6
This shows that the center of the circle (a, b) = (2/3, 0) and radius is ±6
Given:
Right triangle DEF right-angled at F.
ED=97 (hypotenuse)
DF=72 (opposite side of angle E)
FE=65 (adjacent side of angle E)
Cosine of angle E
=(adjacent side)/(hypotenuse)
=FE/ED
=65/97
=0.6701 (to four decimal places)
Answer:
(−3,5)
Step-by-step explanation:
x= −3 , y= 5
Yes the point does remain on a straight line