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hichkok12 [17]
3 years ago
15

Jake's parents want $100,000 at the end of 40 years. They put their money in an account that yields 4% per year compounded conti

nuously. How much money should jakes parents deposit?
Mathematics
1 answer:
Rudik [331]3 years ago
8 0

Answer:

$ 20,189.65

Step-by-step explanation:

Jake's parents want $100,000 at the end of 40 years. They put their money in an account that yields 4% per year compounded continuously. How much money should jakes parents deposit?

From the above question, we are to find the Principal. The formula for Principal compounded continuously =

P = A / e^rt

Where:

A = Amount after time t = $100,000

r = Interest rate = 4%

t = Time in years = 40 years

First, convert R percent to r a decimal

r = R/100

r = 4%/100

r = 0.04 per year,

Then, solve our equation for P

P = A / e^rt

P = 100,000.00 / e ^(0.04×40)

P = $ 20,189.65

Therefore, the amount Jake's parents should invest = $ 20,189.65

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What is -3×^2+1467x-86940=0 ?​
frozen [14]

For this case we must solve the following quadratic equation:

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If we divide both sides of the equation by 3 we have:

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The solutions will come from:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}

Where:

a = -1\\b = 489\\c = -28980

Substituting:

x = \frac {-489 \pm \sqrt {(489) ^ 2-4 (-1) (- 28980)}} {2 (-1)}\\x = \frac {-489 \pm \sqrt {239121-115920}} {- 2}\\x = \frac {-489 \pm \sqrt {123201}} {- 2}\\x = \frac {-489 \pm351} {- 2}

The roots are:

x_ {1} = \frac {-489 + 351} {- 2} = \frac {-138} {- 2} = 69\\x_ {2} = \frac {-489-351} {- 2} = \frac {-840} {- 2} = 420

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x_ {1} = 69\\x_ {2} = 420

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