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fredd [130]
3 years ago
12

The bright-line spectrum of an element in the gaseous phase is produced as

Chemistry
1 answer:
sesenic [268]3 years ago
3 0
Electrons move from higher energy states to lower energy states Hope this helped
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What is the name of the compound N2(g)
zavuch27 [327]
N2 stands for nitrogen.
                             this compound also includes the exact mass.
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                 -Diane
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3 years ago
Describe two ways you could demonstrate an acceleration of 2 meters per second squared?
BaLLatris [955]

Answer:

You could do 88 metars  

Explanation:

7 0
3 years ago
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The diagram shows the structure of an animal cell.
Vera_Pavlovna [14]

Answer:

1

Explanation:

The cell membrane is the protective, semi-permeable membrane surrounding a cell and its contents.

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3 years ago
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Which net ionic equation best represents the reaction that occurs when an aqueous solution of barium chloride is mixed with an a
vovangra [49]

Answer : The net ionic equation will be:

Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The balanced molecular equation will be,

BaCl_2(aq)+Li_2SO_4(aq)\rightarrow 2LiCl(aq)+BaSO_4(s)

The complete ionic equation in separated aqueous solution will be,

Ba^{2+}(aq)+2Cl^-(aq)+2Li^+(aq)+SO_4^{2-}(aq)\rightarrow 2Li^+(aq)+2Cl^-(aq)+BaSO_4(s)

In this equation the species, Li^+\text{ and }Cl^{-} are the spectator ions.

By removing the spectator ions , we get the net ionic equation.

The net ionic equation will be:

Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)

6 0
3 years ago
Let us write the appropriate equilibria and associate the correction <img src="https://tex.z-dn.net/?f=K_b" id="TexFormula1" tit
rosijanka [135]

Explanation:

The relation between K_a\&K_b is given by :

K_w=K_a\times K_b

Where :

K_w=1\times 10^{-14} = Ionic prodcut of water

The value of the first ionization constant of sodium sulfite = K_{a1}=1.4\times 10^{-2}

The value of K_{b1}:

1\times 10^{-14}=1.4\times 10^{-2}\times K_{b1}

K_{b1}=\frac{1\times 10^{-14}}{1.4\times 10^{-2}}=7.1\times 10^{-13}

The value of the second ionization constant of sodium sulfite = K_{a2}=6.3\times 10^{-8}

The value of K_{b2}:

1\times 10^{-14}=6.3\times 10^{-8}\times K_{b1}

K_{b1}=\frac{1\times 10^{-14}}{6.3\times 10^{-8}}=1.6\times 10^{-7}

3 0
3 years ago
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